Question

我正在使用retrofit2和rxjava2按顺序进行多个api调用。我发出请求以获取列表元素。之后，我需要为每个对象制作一个请求序列（不是并行）。

使用递归函数解决

Answer 1

如果您只想执行数组的每个项目。只需使用Observable.just()或Observable.fromIterable()

即可

    List<String> list = Arrays
            .asList("One", "Two", "Three", "Four", "Five");

    Observable<String> observable = Observable.from(list);

    observable.subscribe(new Subscriber<String>() {
        public void onStart() {
            System.out.println("onStart");
        }

        public void onCompleted() {
            System.out.println("Completed!");
        }

        public void onError(Throwable e) {
            System.out.println("Exception thrown: " + e);
        }

        public void onNext(String s) {
            System.out.println("Next element: " + s);
        }
    });

结果是

onStart
Next element: One
Next element: Two
Next element: Three
Next element: Four
Next element: Five
Completed!

使用rxjava2和retrofit2的多个请求

1 个答案: