我正在使用AWS SES,并尝试将zip文件附加到内存中制作的CSV的电子邮件中。我很接近,但我很难搞清楚这一点。目前,当我收到电子邮件时,我仍然收到.CSV,但在打开时,似乎内容是压缩的。如何压缩文件而不是内容?该文件当前是作为一个再见阵列接收的。
public void emailReport(byte[] fileAttachment, String attachmentType,
String attachmentName, List<String> emails) throws MessagingException, IOException {
......
// Attachment
messageBodyPart = new MimeBodyPart();
byte[] test = zipBytes(attachmentName, fileAttachment);
// DataSource source = new ByteArrayDataSource(fileAttachment, attachmentType);
DataSource source = new ByteArrayDataSource(test, "application/zip");
messageBodyPart.setDataHandler(new DataHandler(source));
messageBodyPart.setFileName(attachmentName);
multipart.addBodyPart(messageBodyPart);
log.info("Successfully attached file.");
message.setContent(multipart);
try {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
message.writeTo(outputStream);
RawMessage rawMessage = new RawMessage(ByteBuffer.wrap(outputStream.toByteArray()));
SendRawEmailRequest rawEmailRequest = new SendRawEmailRequest(rawMessage);
client.sendRawEmail(rawEmailRequest);
System.out.println("Email sent!");
log.info("Email successfully sent.");
} catch (Exception ex) {
log.error("Error when sending email");
ex.printStackTrace();
}
}
public static byte[] zipBytes(String filename, byte[] input) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ZipOutputStream zos = new ZipOutputStream(baos);
ZipEntry entry = new ZipEntry(filename);
entry.setSize(input.length);
zos.putNextEntry(entry);
zos.write(input);
zos.closeEntry();
zos.close();
return baos.toByteArray();
}
感谢您的帮助,如果您有任何其他问题,请告诉我,我将提供任何代码等。需要。
答案 0 :(得分:3)
文件名应该是.zip扩展名。
messageBodyPart.setFileName("file.zip");