Question

我有以下代码：

   int main()
{
  string s = "server ('m1.labs.teradata.com') username ('use\\')r_*5') password('u\" er 5') dbname ('default')";

    regex re("(\'[!-~]+\')");
    sregex_token_iterator i(s.begin(), s.end(), re, 1);
    sregex_token_iterator j;

    unsigned count = 0;
    while(i != j)
    {
        cout << "the token is  "<<*i<< endl;
        count++;
    }
    cout << "There were " << count << " tokens found." << endl;

  return 0;
}

使用上面的正则表达式，我想在paranthesis和单引号之间提取字符串：out out应该是这样的：

the token is   'm1.labs.teradata.com'
the token is   'use\')r_*5'
the token is   'u" er 5'
the token is   'default'
There were 4 tokens found.

基本上，正则表达式应该在＆＃34;之间提取所有内容。（＆＃39;＆＃34;和＆＃34;＆＃39;）＆＃34;。它可以是任何空间，特殊字符，引用或结束的parathesis。我之前使用过以下正则表达式：

boost::regex re_arg_values("(\'[!-~]+\')");

但是不接受空间。请有人帮我解决这个问题。提前谢谢。

Answer 1

以下是使用Spirit X3创建语法以实际解析此问题的示例。我想解析（key-＆gt; value）对的映射，这比盲目假设名称总是相同更有意义：

using Config = std::map<std::string, std::string>;
using Entry  = std::pair<std::string, std::string>;

现在，我们使用X3设置一些语法规则：

namespace parser {
    using namespace boost::spirit::x3;

    auto value  = quoted("'") | quoted('"');
    auto key    = lexeme[+alpha];
    auto pair   = key >> '(' >> value >> ')';
    auto config = skip(space) [ *as<Entry>(pair) ];
}

助手as<>和quoted是简单的lambdas：

template <typename T> auto as = [](auto p) { return rule<struct _, T> {} = p; };
auto quoted = [](auto q) { return lexeme[q >> *('\\' >> char_ | char_ - q) >> q]; };

现在我们可以直接将字符串解析为地图：

Config parse_config(std::string const& cfg) {
    Config parsed;
    auto f = cfg.begin(), l = cfg.end();
    if (!parse(f, l, parser::config, parsed))
        throw std::invalid_argument("Parse failed at " + std::string(f,l));
    return parsed;
}

演示程序

int main() {
    Config cfg = parse_config("server ('m1.labs.teradata.com') username ('use\\')r_*5') password('u\" er 5') dbname ('default')");

    for (auto& setting : cfg)
        std::cout << "Key " << setting.first << " has value " << setting.second << "\n";
}

打印

Key dbname has value default
Key password has value u" er 5
Key server has value m1.labs.teradata.com
Key username has value use')r_*5

现场演示

<强> Live On Coliru

#include <iostream>
#include <boost/spirit/home/x3.hpp>
#include <boost/fusion/adapted/std_pair.hpp>
#include <map>

using Config = std::map<std::string, std::string>;
using Entry  = std::pair<std::string, std::string>;

namespace parser {
    using namespace boost::spirit::x3;

    template <typename T> auto as = [](auto p) { return rule<struct _, T> {} = p; };
    auto quoted = [](auto q) { return lexeme[q >> *(('\\' >> char_) | (char_ - q)) >> q]; };

    auto value  = quoted("'") | quoted('"');
    auto key    = lexeme[+alpha];
    auto pair   = key >> '(' >> value >> ')';
    auto config = skip(space) [ *as<Entry>(pair) ];
}

Config parse_config(std::string const& cfg) {
    Config parsed;
    auto f = cfg.begin(), l = cfg.end();
    if (!parse(f, l, parser::config, parsed))
        throw std::invalid_argument("Parse failed at " + std::string(f,l));
    return parsed;
}

int main() {
    Config cfg = parse_config("server ('m1.labs.teradata.com') username ('use\\')r_*5') password('u\" er 5') dbname ('default')");

    for (auto& setting : cfg)
        std::cout << "Key " << setting.first << " has value " << setting.second << "\n";
}

加成

如果您想学习如何提取原始输入：只需尝试

auto source = skip(space) [ *raw [ pair ] ];

如下：

using RawSettings = std::vector<std::string>;

RawSettings parse_raw_config(std::string const& cfg) {
    RawSettings parsed;
    auto f = cfg.begin(), l = cfg.end();
    if (!parse(f, l, parser::source, parsed))
        throw std::invalid_argument("Parse failed at " + std::string(f,l));
    return parsed;
}

int main() {
    for (auto& setting : parse_raw_config(text))
        std::cout << "Raw: " << setting << "\n";
}

打印： Live On Coliru

Raw: server ('m1.labs.teradata.com')
Raw: username ('use\')r_*5')
Raw: password('u" er 5')
Raw: dbname ('default')

Answer 2

修复一些语法和样式问题：

您需要在C字符串

\

s中有"，语法错误

#include <boost/regex.hpp>
#include <boost/range/iterator_range.hpp>
#include <iostream>

int main() {
    std::string s = "server ('m1.labs.teradata.com') username ('use\')r_*5') password('u' er 5') dbname ('default')";

    boost::regex re(R"(('([^'\\]*(?:\\[\s\S][^'\\]*)*)'))");

    size_t count = 0;
    for (auto tok : boost::make_iterator_range(boost::sregex_token_iterator(s.begin(), s.end(), re, 1), {})) {
        std::cout << "Token " << ++count << " is " << tok << "\n";
    }
}

打印

Token 1 is 'm1.labs.teradata.com'
Token 2 is 'use'
Token 3 is ') password('
Token 4 is ' er 5'
Token 5 is 'default'

标记字符串，接受CPP中给定字符集之间的所有内容

2 个答案:

现场演示

加成