Question

我遵循mongoose架构：

{
    "_id" : ObjectId("5971b0a0d5602b15a8068ab7"),
    "trainnum" : "011Ф",
    "startplace" : "Tashkent",
    "destination" : "Samarkand",
    "updated_at" : ISODate("2017-07-21T07:43:28.620Z"),
    "weeks" : [
            "1",
            "2",
            "3",
            "4",
            "5",
            "6",
            "0"
    ],
    "vagons" : [
            {
                    "_id" : ObjectId("5971daead5602b15a8068abd"),
                    "numvag" : "01K",
                    "seatcount" : "40",
                    "reserves" : [
                            {
                                    "numseats" : "1-10",
                                    "numreserve" : "1",
                                    "_id" : ObjectId("5971daead5602b15a8068abf")
                            },
                            {
                                    "numseats" : "11-27",
                                    "numreserve" : "2",
                                    "_id" : ObjectId("5971daead5602b15a8068abe")
                            }
                    ],
                    "date2" : ISODate("2017-07-21T00:00:00Z"),
                    "date1" : ISODate("2017-07-21T00:00:00Z")
            }
    ],
    "date2" : ISODate("2017-12-31T00:00:00Z"),
    "date1" : ISODate("2017-01-01T00:00:00Z"),
    "__v" : 0
}

我想在特定日期使numvag独一无二。我的意思是它不允许我为现有的date1和date2添加相同的numvag值。

Answer 1

通过mongoose-unique-validator安装npm install mongoose-unique-validator （https://www.npmjs.com/package/mongoose-unique-validator）

到您的正常架构，

const myScheme = Mongoose.Schema({
  email : { required: true }
})

要求模块并附加＆＃34; uniqueValidator＆＃34;到最后如下，

const uniqueValidator = require('mongoose-unique-validator');

const myScheme = Mongoose.Schema({
  email : { required: true }
}).plugin(uniqueValidator);

现在，您可以添加除默认模式之外的其他模式

const uniqueValidator = require('mongoose-unique-validator');

const myScheme = Mongoose.Schema({
  email : { 
    required: true,
    unique: true
}
}).plugin(uniqueValidator);

因此，如果您尝试为电子邮件插入相同的记录，则会引发错误。

如何创建允许为特定日期插入唯一值的mongoose模式

1 个答案: