Question

我正在尝试使用while()循环返回名为orders的表中的所有数据，并将它们打印在HTML表中。

我尝试了两种循环数据的方法。

while($row = mysqli_fetch_assoc($result))
while($row = $result->fetch_assoc())

两种方式都只将第一行添加到我的HTML表格中，只回显到任何其他行的页面。

以下是代码：

<!DOCTYPE html>
<html>
<head>
<title>Page Title</title>
</head>
<body>

<h1>FORM SUCCESSFULLY SENT</h1>

<p>Here are the order details</p>

<?php
    $servername = xxxx;
    $username = xxxx;  
    $password = xxxx;  
    $databasename = xxxx;
    $conn = new mysqli($servername, $username, $password, $databasename);           // Create connection
    if ($conn->connect_error) die("Connection failed: " . $conn->connect_error);    // Check connection
    $sql_query = "SELECT * FROM orders";
    $result = mysqli_query($conn,$sql_query);

?>
<table border="3" style= "background-color: #84ed86; color: #761a9b; margin: 5 auto;" >
      <thead>
        <tr>
          <th>Name</th>
          <th>Surname</th>
          <th>Start City</th>
          <th>End City</th>
          <th>Tracking Number</th>
        </tr>
      </thead>
      <tbody>
        <?php
          if (!$result) throw new Exception('Database error: ' . mysql_error());
          else
          {
              while($row = mysqli_fetch_assoc($result))
              {
                 echo "<tr>";
                 echo "<td>".$row['client_name']."</td>";
                 echo "<td>".$row['client_surname']."</td>";
                 echo "<td>".$row['client_start_city']."</td>";
                 echo "<td>".$row['client_end_city']."</td>";
                 echo "<td>".$row['order_tracking_number']."</td>";
                 echo "</tr>";
                 echo "</table>";
              }
              $result->free();  // free result set
          }
        ?>
      </tbody>
    </table>
<?php 
      $conn->close(); 
?>

</body>
</html>

这就是我回来的原因

Answer 1

我看到3条记录。删除：

echo "</table>";

来自while循环，它会起作用！：）

Answer 2

您的echo "</table>";需要超出while：

while($row = mysqli_fetch_assoc($result))
{
     echo "<tr>";
     echo "<td>".$row['client_name']."</td>";
     echo "<td>".$row['client_surname']."</td>";
     echo "<td>".$row['client_start_city']."</td>";
     echo "<td>".$row['client_end_city']."</td>";
     echo "<td>".$row['order_tracking_number']."</td>";
     echo "</tr>";
}
echo "</table>";

Answer 3

每件事都很好!!只需echo "</table>"; 从While循环中移除此内容。

 <?php
          if (!$result) throw new Exception('Database error: ' . mysql_error());
          else
          {
              while($row = mysqli_fetch_assoc($result))
              {
                 echo "<tr>";
                 echo "<td>".$row['client_name']."</td>";
                 echo "<td>".$row['client_surname']."</td>";
                 echo "<td>".$row['client_start_city']."</td>";
                 echo "<td>".$row['client_end_city']."</td>";
                 echo "<td>".$row['order_tracking_number']."</td>";
                 echo "</tr>";
                 //echo "</table>"; Remove This.
              }
              $result->free();  // free result set
          }
        ?>

我只得到了我桌子的第一排

3 个答案: