我想在我的聊天应用程序中使用{:redix,“〜> 0.6.1”}十六进制包并从监督树开始
{:ok, conn} = Redix.start_link()
{:ok, conn} = Redix.start_link(host: "example.com", port: 5000)
{:ok, conn} = Redix.start_link("redis://localhost:6379/3", name: :redix)
Redix.command(conn, ["SET", "mykey", "foo"])
但是当我尝试将连接开始链接放到子进程
时,它会出错children = [
# Start the Ecto repository
supervisor(PhoenixChat.Repo, []),
# Start the endpoint when the application starts
supervisor(PhoenixChat.Endpoint, []),
# Start your own worker by calling: PhoenixChat.Worker.start_link(arg1, arg2, arg3)
# worker(PhoenixChat.Worker, [arg1, arg2, arg3]),
supervisor(PhoenixChat.Presence, []),
#supervisor(Phoenix.PubSub.Redis, [:chat_pubsub, host: "127.0.0.1"])
]
如何启动redix连接并将数据存储到Redis?
答案 0 :(得分:5)
您要做的是Register
进程ID。为此,您通常可以在opts中指定其名称,如下所示:
worker(Redix, [[], [name: RedixConnection]])
当进程注册时,通常可以使用它的名称而不是PID(总是检入文档,但这是常见模式),如下所示:
Redix.command(RedixConnection, ["PING"])
大多数情况下,一个连接是不够的。您可能希望使用某种池化机制,如poolboy
。 documentation中有一个非常简洁的页面供您阅读,其名称为Real-world usage
。它可能会回答与此主题相关的大多数问题。
请考虑为您的事业使用Erlang / Elixir内置解决方案。我不知道您的确切用例,但您可能想查看ETS,DTS和Mnesia。
答案 1 :(得分:1)
children = [
# Start the Ecto repository
supervisor(PhoenixChat.Repo, []),
# Start the endpoint when the application starts
supervisor(PhoenixChat.Endpoint, []),
# Start your own worker by calling: PhoenixChat.Worker.start_link(arg1, arg2, arg3)
# worker(PhoenixChat.Worker, [arg1, arg2, arg3]),
supervisor(PhoenixChat.Presence, []),
worker(Redix, [[], [name: :redix]]),
#supervisor(Phoenix.PubSub.Redis, [:chat_pubsub, host: "127.0.0.1"])
]
Redix.command(:redix, ["SET", "key", "value"])