Question

我正在创建一个练习python的简单脚本;它会计算名称中的字符，也可以检测连字符和空格;但我有一个问题 示例代码：

text = input('enter hyphen and space:')
if '-' in text:
    print('hyphen in text')
elif ' ' in text:
    print('space in text')
elif ' ' and '-' in text:
    print('hyphen and space in text')
else:
    print('Nothing :( ')

当用户在文本中同时写下空格和连字符时，它会显示hyphen in text
我怎样才能防止这种情况发生？ 主要代码：

name = input('Enter your name:')
from time import sleep
if ' ' in name:
    print('Looks like your name contain spaces')
    sleep(0.6)
    op1 = input('Count spaces in it? y/n\n')
    sleep(0.6)
    if op1.lower() == 'y':
        name = len(name)
        print('Numbers in your name: ',name)
    if op1.lower() != 'y':
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
elif '-' in name:
    print('Looks like your name contain hyphens ( - )')
    sleep(0.6)
    op = input('Count hyphens in it? y/n\n')
    sleep(0.6)
    if op.lower() == 'y':
        name = len(name)
        print('Numbers in your name: ',name)
    if op.lower() != 'y':
        name = name.replace('-','')
        name = len(name)
        print('Numbers in your name: ',name)
if '-' and ' ' in name:
    print('Looks like your name contain both hyphen/s and space/s')
    sleep(0.6)
    print('options:\n')
    sleep(0.8)
    print('1) Count hyphen/s')
    print('2) Count space/s')
    print('3) Count both')
    print('4) Skip both')
    sleep(1)
    op = input('1 / 2 / 3 \nEnter your choice:')
    op = op.lower()
    sleep(0.6)
    if op == '1':
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
    if op == '2':
        name = name.replace('-','')
        name = len(name)
        print('Numbers in your name: ',name)
    if op == '3':
        print('Numbers in your name: ',name)
    if op == '4':
        name = name.replace('-','')
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
else:
    name = len(name)
    print('Numbers in your name: ',name)

Answer 1

在顶部设置复杂条件，也不要忘记重复检查in text，因为

' ' and '-' in text

如果True中只有连字符，那么

将为text，因为' '是True - 就像字符串一样，你应该这样做：

' ' in text and '-' in text

最后我们可以有像

这样的东西

if ' ' in text and '-' in text:
    print('hyphen and space in text')
elif '-' in text:
    print('hyphen in text')
elif ' ' in text:
    print('space in text')
else:
    print('Nothing :( ')

Answer 2

当您的输入流入if语句时，将检查第一个条件。该条件为'-' in text，如果True将评估为text = "- "，然后退出if语句。我们要找的是首先检查最具体的案例，即' ' and '-' in text。所以正确的程序看起来像这样：

text = input('enter hyphen and space:')
if ' ' in text and '-' in text:
    print('hyphen and space in text')
elif '-' in text:
    print('hyphen in text')
elif ' ' in text:
    print('space in text')
else:
    print('Nothing :( ')

Answer 3

条件语句的顺序是这里的问题，因为它总是会进入第一个if，即if '-' in text，如示例中的连字符和空格都存在。此外，由于检查这两种情况的条件是elif，因此永远不会执行。

所以你必须要有自己的病情， " " and "_" in text在第一个。

永远记住，如果，elif（可选），else按顺序工作，并且只根据你的条件执行块的一部分。

注意：如果任何非字符串输入像整数一样给出，则代码将抛出错误。所以我添加了raw_input，你总是可以使用它将它转换为你想要的数据类型，甚至可以使用异常处理。

所以你的实际代码应该是这样的，

name = raw_input('Enter your name:')
from time import sleep
if '-' and ' ' in name:
    print('Looks like your name contain both hyphen/s and space/s')
    sleep(0.6)
    print('options:\n')
    sleep(0.8)
    print('1) Count hyphen/s')
    print('2) Count space/s')
    print('3) Count both')
    print('4) Skip both')
    sleep(1)
    op = input('1 / 2 / 3 \nEnter your choice:')
    op = op.lower()
    sleep(0.6)
    if op == '1':
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
    if op == '2':
        name = name.replace('-','')
        name = len(name)
        print('Numbers in your name: ',name)
    if op == '3':
        print('Numbers in your name: ',name)
    if op == '4':
        name = name.replace('-','')
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
elif ' ' in name:
    print('Looks like your name contain spaces')
    sleep(0.6)
    op1 = input('Count spaces in it? y/n\n')
    sleep(0.6)
    if op1.lower() == 'y':
        name = len(name)
        print('Numbers in your name: ',name)
    if op1.lower() != 'y':
        name = name.replace(' ','')
        name = len(name)
        print('Numbers in your name: ',name)
elif '-' in name:
    print('Looks like your name contain hyphens ( - )')
    sleep(0.6)
    op = input('Count hyphens in it? y/n\n')
    sleep(0.6)
    if op.lower() == 'y':
        name = len(name)
        print('Numbers in your name: ',name)
    if op.lower() != 'y':
        name = name.replace('-','')
        name = len(name)
        print('Numbers in your name: ',name)

else:
    name = len(name)
    print('Numbers in your name: ',name)

从python中的输入中检测连字符和空格？

3 个答案: