Question

我正在尝试创建一个函数来完成以下哈希中的小时序列。

{
  name: "cardio", 
  data: [["06:00", 999], ["09:00", 154], ["10:00", 1059], ["11:00", 90]]
}

它应该在字段数据中创建所有缺失值

["07:00", 0], ["08:00", 0], ["12:00", 0], ["13:00", 0] ... ["23:00", 0]

预期结果：

{
 name: "cardio", 
 data: [["06:00", 999], ["07:00", 0], ["08:00", 0], ["09:00", 154], ["10:00", 1059], ["11:00", 90]], ["12:00", 0], ["13:00", 0] ... ["23:00", 0]
}

有可能吗？类似的东西：

data.each do |row|
 (6..23).each do |hour|
  .....
  end
end

Answer 1

您可以使用Array#assoc执行以下操作：

搜索一个数组，其元素也是使用obj。==将obj与每个包含数组的第一个元素进行比较的数组。

input = {
  name: "cardio",
  data: [["06:00", 999], ["09:00", 154], ["10:00", 1059], ["11:00", 90]]
}

input[:data] = 24.times.collect do |hour|
  hour = "%02d:00" % hour

  input[:data].assoc(hour) || [hour, 0]
end

puts input.inspect
# {:name=>"cardio", :data=>[["00:00", 0], ["01:00", 0], ["02:00", 0], ["03:00", 0], ["04:00", 0], ["05:00", 0], ["06:00", 999], ["07:00", 0], ["08:00", 0], ["09:00", 154], ["10:00", 1059], ["11:00", 90], ["12:00", 0], ["13:00", 0], ["14:00", 0], ["15:00", 0], ["16:00", 0], ["17:00", 0], ["18:00", 0], ["19:00", 0], ["20:00", 0], ["21:00", 0], ["22:00", 0], ["23:00", 0]]}

Answer 2

数据

h = {name:"cardio", data:[["06:00", 999], ["09:00", 154], ["10:00", 1059], ["11:00", 90]]}
first =  7
last  = 23

代码的

mdata = (first..last).each_with_object(h[:data].to_h) { |hour,g|
  g["%02d:00" % hour] ||= 0 }.sort
  #=> [["06:00", 999], ["07:00", 0], ["08:00", 0], ["09:00", 154], ["10:00", 1059],
  #    ["11:00", 90], ["12:00", 0],..., ["21:00", 0], ["23:00", 0]]
h.merge(h).merge(data: mdata)
  #=> {:name=>"cardio",
  #    :data=>[["06:00", 999], ["07:00", 0], ["08:00", 0], ["09:00", 154],
  #            ["10:00", 1059], ["11:00", 90], ["12:00", 0],...["23:00", 0]]

如何在散列中的数字序列之后生成和填充缺失的数据

2 个答案: