Question

我有两个单独的查询，我写的并试图合并，但这对我来说太复杂了。第一个查询是一个子查询，它返回经销商编号列表，没有任何重复的数字。第二个查询返回经销商编号列表，其中包含多个重复的经销商编号和经销商余额。我需要查看第一个查询中的经销商编号出现在第二个查询中的次数。目前，我将查询结果复制并粘贴到Excel中，然后使用Countif功能查看第一个查询中的经销商在第二个查询中出现的次数。

有没有办法在SQL中执行整个过程？

查询1

SELECT DISTINCT(X.PARENTS) AS "UNIQUE PARENTS" FROM ( SELECT

CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END AS "PARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END, CUSTMR_NBR
) X

WHERE X.FRANCHISE = 'N'

查询2

SELECT CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END AS "DUPLICATE PARENTS",

SUM(CURR_PRINCPL_AMT)

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END, CUSTMR_NBR

Answer 1

Select Count(PARENT_CUSTMR_NBR) From
(
SELECT DISTINCT(X.PARENTS) AS "UNIQUE PARENTS" FROM ( SELECT

CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR 
END AS "PARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 
THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR ) X

WHERE X.FRANCHISE = 'N')
Where PARENT_CUSTMR_NBR
IN
(SELECT CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END AS "DUPLICATE PARENTS",

SUM(CURR_PRINCPL_AMT)

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR)

Answer 2

我得到了它的工作，感谢你的帮助Suresh！这是最后的查询：

Select Count(DUPPARENTS) From

(SELECT CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END AS "DUPPARENTS"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR)

Where (DUPPARENTS) IN

(SELECT DISTINCT(X.UNIPARENTS) FROM ( SELECT

CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR 
END AS "UNIPARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 
THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR ) X

WHERE X.FRANCHISE = 'N')

我需要计算在两个不相关的复杂查询上重复的条目

2 个答案: