Question

我正在尝试将数据从表单上传到MySQL数据库，但它无法正常工作。

它只是停留在那里并且什么也不做，它不会插入到数据库中。

请查看下面的代码。

<?php
        if(isset($_POST['submit'])) {
        $first_name = $_POST['first_name'];
        $last_name = $_POST['last_name'];
        $username = $_POST['username'];
        $password = md5($_POST['password']);

        $query  = "INSERT INTO users (";
            $query .= "  first_name, last_name, username, password";
            $query .= ") VALUES (";
            $query .= " '{$first_name}', '{$last_name}', '{$username}', '{$password}'";
            $query .= ")";
            $result = mysqli_query($connection, $query);


        if($result) {
            echo "It worked";
        } else {
            echo "It did not work";
        }
        }   


?>

这是我的HTML

           <div class="col-md-8 col-xs-12">
                    <div class="white-box">
                        <form class="form-horizontal form-material" method="post">
                            <div class="form-group">
                                <label class="col-md-12">First Name</label>
                                <div class="col-md-12">
                                    <input type="text" placeholder="John" name="first_name" class="form-control form-control-line"> </div>
                            </div>
                            <div class="form-group">
                                <label class="col-md-12">Last Name</label>
                                <div class="col-md-12">
                                    <input type="text" placeholder="Doe" name="last_name" class="form-control form-control-line"> </div>
                            </div>

                            <div class="form-group">
                                <label class="col-md-12">Username</label>
                                <div class="col-md-12">
                                    <input type="text" placeholder="Username" name="username" class="form-control form-control-line"> </div>
                            </div>
                            <div class="form-group">
                                <label class="col-md-12">Password</label>
                                <div class="col-md-12">
                                    <input type="password" placeholder="Password" name="password" class="form-control form-control-line"> </div>
                            </div>
                            <div class="form-group">
                                <div class="col-sm-12">
                                    <button class="btn btn-success">Create User</button>
                                </div>
                            </div>
                        </form>
                    </div>
                </div>
            </div>
        </div>

Answer 1

由于您正在检查isset（$ _ POST [＆＃34; submit＆＃34;]），您需要在html表单中添加类型为submit的输入标记。

替换

<button class="btn btn-success">Create User</button>

带

<input class="btn btn-success" type="submit" name="submit" value="Create User">

Answer 2

<?php
if (isset($_POST['submit'])) {
 $first_name = $_POST['first_name'];
        $last_name = $_POST['last_name'];
        $username = $_POST['username'];
        $password = ($_POST['password']);



$query=mysqli_query($conn,"INSERT INTO users(first_name, last_name, username, password) VALUES ('$first_name','$last_name','$username','$password')");
   if(!$query){
        die('could not enter data:'. mysqli_error($conn));
    }
    else{
        echo "Entered data successfully";
    }


}
?>

Answer 3

<?php
        if(isset($_POST['submit'])) {
            $first_name = $_POST['first_name'];
            $last_name = $_POST['last_name'];
            $username = $_POST['username'];
            $password = md5($_POST['password']);

            $query  = "INSERT INTO users (first_name, last_name, username, password) VALUES ('$first_name','$last_name','$username','$password')";
            $result = mysqli_query($connection, $query);


            if($result) {
                echo "It worked";
            } else {
                echo "It did not work";
            }
        }   


?>

Answer 4

<!DOCTYPE html>
<html>
<body>

<form  method="post" action="">

                                First Name

                                    <input type="text"  name="first_name" > 

                                Last Name

                                    <input type="text"  name="last_name" class="form-control form-control-line"> 

                                Username

                                    <input type="text" placeholder="Username" name="username" > 

                                Password

                                    <input type="password" placeholder="Password" name="password" > 
                         <input type="submit" name="update" value="create user">

                        </form>
</body>
</html>

<?php
    $host = "localhost";
$username = "root";
$password = "";


$conn = mysqli_connect($host,$username,$password);
mysqli_select_db($conn,'db');            //database name is "db"
if (!$conn){
    die("could not create connection");
}
else
    echo"conection made <br>";
if (isset($_POST['update'])) {
        $first_name = $_POST['first_name'];
        $last_name = $_POST['last_name'];
        $username = $_POST['username'];
        $password = ($_POST['password']);



$query=mysqli_query($conn,"INSERT INTO users(first_name, last_name, username, password) VALUES ('$first_name','$last_name','$username','$password')");
   if(!$query){
        die('could not enter data:'. mysqli_error($conn));
    }
    else{
        echo "Entered data successfully";
    }


}
?>

将数据从表单上传到MySQL数据库

4 个答案: