Question

我是Python新手，这是我尝试的第一语言。我开始了解它的一点点，只需要一些帮助。我正在使用下面的代码制作一个简单的计算器，我想知道如何从头开始重新启动我的代码（你可以在底部看到我的尝试）。

import math
import time

def game():
    def add(x, y):
        return x + y

    def subtract(x, y):
        return x - y

    def multiply(x, y):
        return x * y

    def divide(x, y):
        return x / y

    print("What would you like to do?")
    print("1. Add")
    print("2. Subtract")
    print("3. Multiply")
    print("4. Divide")
    a = int(input("Please choose 1, 2, 3, or 4."))

    def choice():
        if a == 1:
            print("You are now adding.")
        elif a == 2:
            print("You are now subtracting.")
        elif a == 3:
            print("You are now multiplying.")
        elif a == 4:
            print("You are now dividing.")
    choice()

    first_num = int(input("What is the first number you want to use?"))
    time.sleep(2)
    second_num = int(input("What is the second number you want to use?"))
    time.sleep(2)

    def execute():
        if a == 1:
            print(first_num, "+", second_num, "=", add(first_num,second_num))
        elif a == 2:
            print(first_num, "-", second_num, "=", subtract(first_num,second_num))
        elif a == 3:
            print(first_num, "x", second_num, "=", multiply(first_num,second_num))
        elif a == 4:
            print(first_num, "/", second_num, "=", divide(first_num,second_num))
    execute()

game()

def playagain():
    input("Would you like to calculate another problem? Yes or No")

playagain()

while playagain == "Yes":
    game()

Answer 1

您可以使用简单的loop来执行此操作，例如：

play_again = True
while play_again:
    # your code goes here
    inp = input("Would you like to calculate another problem? Yes or No")
    play_again = inp.lower() == 'yes'

如果输入不是

，这会将play_again更改为False

Answer 2

您非常接近可行的解决方案：

return

您需要playagain()从输入中键入的值，然后import xmltodict def start_requests(self): yield Request("https://www.gotdatjuice.com/sitemap.xml", callback=self.parse_sitemap) def parse_sitemap(self,response): obj = xmltodict.parse(response.body) monString = json.dumps(obj) json_data = json.loads(monString) urls = json_data['urlset']['url'] for url in urls : loc = url['loc']会询问它们并将该值插入其中，然后将其与“是”进行比较。

您当前的方法没有什么特别的错误。

Answer 3

你最终真的接近逻辑。不需要while语句，只需要if语句。

playagain = input("Would you like to calculate another problem? Yes or No")
if playagain == "Yes":
    game()

如果您想在问题解决后继续询问，那么您可以在游戏功能内部而不是在外部执行if else，因此在询问问题后它将继续询问playagain变量。

playagain = raw_input("Would you like to calculate another problem? Yes or No")
if playagain == "Yes":
    game()
else:
    return

在Python中重新启动代码

3 个答案: