如何在JGAP的初始人群中设置一个独特的染色体？

Question

我正在尝试执行以下操作：我有一个N型染色体，其类型为IntegerGene。我对在交叉算子后评估的唯一染色体感兴趣，所以我使用：

            Configuration configuration = new DefaultConfiguration ();
            Configuracion.getGeneticOperators (). Clear ();
            CrossoverOperator crossover = new CrossoverOperator (configuration);
            Configuracion.addGeneticOperator (crossover);
            ...
            Genotype poblacion = Genotype.randomInitialGenotype(configuracion);

例如，我想使用单个染色体来创建以下群体，这个染色体将是| 9 | 5 | 10 | 0 |因此我将其初始化：

 Gene [] genes = new Gene [4];

 genes [0] = new IntegerGene (configuration, 9,9);
 genes [1] = new IntegerGene (configuration, 5,5);
 genes [2] = new IntegerGene (configuration, 10,10);
 genes [3] = new IntegerGene (configuration, 0,0);

当我运行程序时，输出（染色体解决方案）始终相同（| 9 | 5 | 10 | 0 |），它不执行交叉运算符....

Run:
Population Size: 10

...
 9 5 10 0
Punctuation = 12.5
 9 5 10 0
Punctuation = 12.5
 9 5 10 0
Punctuation = 12.5
 9 5 10 0
Punctuation = 12.5

 Chromosome Solution [0] = 9
 Chromosome Solution [1] = 5
 Chromosome Solution [2] = 10
 Chromosome Solution [3] = 0

谢谢。