Question

我有2个带键和值的哈希

h1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6}

h2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14}

我期待得到像

这样的结果

result = {3=>1, 5=>2, 10=>4, 12=>5, 14=>6}

我试过这个解决方案

如果你想要1回复＆＃34;首先＆＃34;和＆＃34;一个＆＃34;，你需要存储它们在一个数组中，然后是1映射到的数值。

results = {}

  hash1.each do |key, value|   if results[key].nil?
     results[key] = [value]   else
     results[key] << value

hash2.each do |key, value|   if results[key].nil?
     results[key] = [value]   else
     results[key] << value

results[1]
# => ["one", "first"]

但我的结果是

{1=>[3], 2=>[5], 3=>[10], 4=>[12], 6=>[14], "January"=>[1], "February"=>[2], "March"=>[4], "April"=>[5], "May"=>[5], "June"=>[6]}

Answer 1

这是因为你把它放在一个列表中，尝试做跟随，不需要做第二个foreach循环：

推荐方式：

hash1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6}

hash2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14}

results = {}

#here you have to swap key-value for value-key

hash2.each do |value, key| 
  if results[key].nil?
    results[key] = value
  else 
    results[key] << value
  end
end

results

=＆GT; {3 =＆gt; 1,5 =＆gt; 2,10 =＆gt; 3,12 =＆gt; 4,14 =＆gt; 6}

替代方式：

您可以压缩两个列表，一个键，另一个值，然后将它们放在字典中：

hash1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6}

hash2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14}

results = {}

(hash2.values).zip(hash1.values).each do |key, value| 
  if results[key].nil?
    results[key] = value
  else 
    results[key] << value
  end
end

results

=＆GT; {3 =＆gt; 1,5 =＆gt; 2,10 =＆gt; 4,12 =＆gt; 5,14 =＆gt; 5}

合并两个哈希值

1 个答案: