我正在尝试编写一个程序,将用户输入的英寸数转换为英尺,码和英里。下面是我的工作代码,但是,我需要将每个转换(英尺/码/英里)分成不同的方法,这些方法将从main调用。我怎样才能做到这一点?
class Program
{
static void Main(string[] args)
{
int feet = 12;
int yards = 36;
int miles = 63360;
Console.WriteLine("How many inches would you like to convert?");
int inches = Convert.ToInt32(Console.ReadLine());
double numOfFeet = (double)inches / feet;
double numOfYards = (double)inches / yards;
double numOfMiles = (double)inches / miles;
Console.WriteLine(inches + " inches is equivalent to " + string.Format("{0:N2}", numOfFeet) + " feet, or " + string.Format("{0:N2}", numOfYards) + " yards, or " + string.Format("{0:N2}", numOfMiles) + " miles.");
Console.ReadLine();
}
}
答案 0 :(得分:0)
这应该是:
Set<Set.Element>
你的主人会简单地称他们为:
static double ConvertInchesToFeet(double inches){
//code for inches to feet
}
static double ConvertInchesToYards(double inches){
//code for inches to Yards
}
static double ConvertInchesToMiles(double inches){
//code for inches to Miles
}
答案 1 :(得分:0)
注意每次只传入Inches
的新方法的逻辑抽象并返回一个double类型。
static void Main(string[] args)
{
Console.WriteLine("How many inches would you like to convert?");
int inches = Convert.ToInt32(Console.ReadLine());
double numOfFeet = ConvertToFeet(inches);
double numOfYards = ConvertToYards(inches);
double numOfMiles = ConvertToMiles(inches);
Console.WriteLine(inches + " inches is equivalent to " + string.Format("{0:N2}", numOfFeet) + " feet, or " + string.Format("{0:N2}", numOfYards) + " yards, or " + string.Format("{0:N2}", numOfMiles) + " miles.");
Console.ReadLine();
}
private static double ConvertToMiles(int inches)
{
int miles = 63360;
return inches / miles;
}
private static double ConvertToYards(int inches)
{
int yards = 36;
return inches / yards;
}
private static double ConvertToFeet(double inches)
{
int feet = 12;
return inches / feet;
}
}
答案 2 :(得分:0)
您需要使用静态方法。它们看起来像这样:
static double InchesToFeet(int inches)
{
return (double)inches / 12;
}
static double InchesToYards(int inches)
{
return (double)inches / 36;
}
static double InchesToMiles(int inches)
{
return (double)inches / 63360;
}
要调用它们,您只需在主体中使用方法调用,如下所示:
double result = InchesToFeet(inches);
答案 3 :(得分:0)
您可以通过两种方式在控制台应用程序中完成此任务:
使用控制台应用程序时,请务必注意该类是静态类。因此,如果要在控制台应用程序中定义静态方法/函数,则需要静态方法/函数。
因此,选项1:
static void CalcuateFeet(int inches)
{
Console.WriteLine("Inches as feet:" + ((double)inches) / 12.0;
}
选项2:
static double CalcuateFeet(int inches)
{
return ((double)inches) / 12.0;
}