Question

我有这个django代码

Build->Build APK

当我尝试

时

CreateMap<Source, Dest>(MemberList.Source)

我得到结果

q1 = MyModel.objects.all()
q2 = MyModel.objects.all()

那么如何检查django中的两个查询集结果是否等于？

Answer 1

您可以将查询集转换为列表并检查它们是否相等：

q1 = Model.objects.all()
q2 = Model.objects.all()
equal = True
for idx, q in q1:
    if q != q2[idx]:
       equal = False
print(equal)

Answer 2

尝试一下：

q1.intersection(q2).count() == q1.count() and q1.count() == q2.count()

Answer 3

您可以将其转换为集合，以检查2个查询集合是否具有相同的元素（尽管有序）。

set(lit(q1)) == set(list(q1))

它将返回：

True

Answer 4

我花了2美分作为一个函数，该函数比较两个QuerySet是否相等，而忽略排序顺序。注意，我实际上并没有检查QuerySet是否为空。我会留给你。

def querysets_are_same(qs1, qs2, exclude_fields=[]):
     '''
     Check whether two queryset have the same content, sort order of querysets is ignored.

     Params:
     -------
     qs1 (QuerySet) - first queryset to compare
     qs2 (QuerySet) - second queryset to compare
     exclude_fields (list) - fields to exclude from comparison; primary key field is automatically removed.

     Yield:
     ------
     True if both querysets contain the same data while ignoring sort order; False otherwise
     '''

     # lookup primary key field name
     pk_qs1 = qs1[0]._meta.pk.name
     pk_qs2 = qs2[0]._meta.pk.name

     # update excluded fields
     exclude_fields_qs1 = set(exclude_fields) | set([pk_qs1])
     exclude_fields_qs2 = set(exclude_fields) | set([pk_qs2])

     # convert queryset to list of dicts excluding fields
     list_qs1 = [{k:v for k,v in d.items() if not k in exclude_fields_qs1} for d in qs1.values()]
     list_qs2 = [{k:v for k,v in d.items() if not k in exclude_fields_qs2} for d in qs2.values()]

     # sort lists
     list_qs1_sorted = sorted(sorted(d.items()) for d in list_qs1)
     list_qs2_sorted = sorted(sorted(d.items()) for d in list_qs2)

     return list_qs1_sorted == list_qs2_sorted

Answer 5

您可以通过.count（）或：

查看

size

Django检查查询集是否等于

5 个答案: