我正在使用Angular ui-select。我的模特& ui-select选项数组是不同的。在更改值时,它未更新且未显示选项。我将选定的对象Id存储在" pmpo"中,我想在加载时从pmptnk对象数组中显示所选对象。但是没有用。有人说出我做错了什么。
我的模型
中的对象 pmpo:877
pmptnk:[0:
632:{id: "632", pid: "2993", ESID: "9154", lb1: "Undddd", lb2: "219"}
877:{id: "877", pid: "2993", ESID: "9154", lb1: "Pcddd", lb2: "29"}
654:{id: "654", pid: "2993", ESID: "9154", lb1: "kukuu", lb2: "246"}]
在视图文件
中 <div ng-if="item.pmptnk.length > 0">
<ui-select ng-model="item.pmpo" click-out-side="closeThis($event)">
<ui-select-match placeholder="Select " search-placeholder="Filter Tanks"
uib-tooltip="{{item.pmpo > 0 ? $select.selected.lb1 : 'Select Tank'}}" tab-select="true">
<span ng-bind="$select.selected.lb1"></span>
</ui-select-match>
<ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">
<span ng-bind="obj.lb1"></span>
</ui-select-choices>
<ui-select-no-choice>
No results matched "{{$select.search}}"
</ui-select-no-choice>
</ui-select>
</div>
答案 0 :(得分:1)
根据docs of ui-select-choices
,repeat
属性
指定要作为选项提供的项目列表。语法类似 到ngRepeat 。
可以让ngRepeat迭代一个属性 使用以下语法对象:
<div ng-repeat="(key, value) in myObj"> ... </div>
因此,从此我们可以得出结论,您应该更改语法:
<ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">
到此:
<ui-select-choices repeat="(key, value) in (item.pmptnk[item.pmpo])">
其中value
为877
,2993
等等,key
为id
,pid
等等。
答案 1 :(得分:0)
我处理了你的代码。我以不同的方式尝试了它。 以下是我的代码段:
<div ng-if="item.pmptnk.length > 0">
<ui-select ng-model="item.selected" click-out-side="closeThis($event)">
<ui-select-match placeholder="Select " search-placeholder="Filter Tanks" uib-tooltip="{{item.pmpo > 0 ? $select.selected.lb1 : 'Select Tank'}}" tab-select="true">
<span ng-bind="$select.selected.lb1"></span>
</ui-select-match>
<ui-select-choices repeat="obj.tid as obj in (item.pmptnk)">
<span ng-bind="obj.lb1"></span>
</ui-select-choices>
<ui-select-no-choice>
No results matched "{{$select.search}}"
</ui-select-no-choice>
</ui-select>
我改变了我的模型如下:
$scope.item = {};
$scope.item.pmpo=877;
$scope.item.pmptnk=[
{id: "632", pid: "2993", ESID: "9154", lb1: "Undddd", lb2: "219"},
{id: "877", pid: "2993", ESID: "9154", lb1: "Pcddd", lb2: "29"},
{ id: "654", pid: "2993", ESID: "9154", lb1: "kukuu", lb2: "246" }];
for (var i = 0 ; i < $scope.item.pmptnk.length; i++) {
if ($scope.item.pmptnk[i].id == $scope.item.pmpo) {
$scope.item.selected = $scope.item.pmptnk[i].tid;
break;
}
}
这对我来说很好。
答案 2 :(得分:-1)
不应该是ng-repeat而不是重复吗?
<ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">
将此行更改为以下
<ui-select-choices ng-repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">
希望能解决这个问题。