Question

我创建了一个onClick函数，该函数创建折线并显示toast。我想在点击按钮后每5秒重复一次这个功能。我该怎么做？

@Override
public void onClick(View view){

    Toast.makeText(getActivity(), "Track erstellen", Toast.LENGTH_SHORT).show();

    for (int e=0 ; e < points.size();e++) {
        options = new PolylineOptions().width(7).color(Color.rgb(0, 139, 69)).geodesic(true);
        for (int i = 0; i < points.size(); i++) {
            LatLng point = points.get(i);
            options.add(point);
        }
        line = mGoogleMap.addPolyline(options);
    }
}

Answer 1

重复调用它为它创建一个函数

public void onClickMethod(){
    Toast.makeText(getActivity(), "Track erstellen", Toast.LENGTH_SHORT).show();

    for (int e=0 ; e < points.size();e++) {
        options = new PolylineOptions().width(7).color(Color.rgb(0, 139, 69)).geodesic(true);
        for (int i = 0; i < points.size(); i++) {
            LatLng point = points.get(i);
            options.add(point);
        }
        line = mGoogleMap.addPolyline(options);
    }
    Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            onClickMethod();
        }
    },5000);
}

其中5000是你的5秒延迟

并在onClick方法中调用onClickMethod（）;

Answer 2

计时器将帮助您每5秒钟调用一次功能。

 public void timer() 
        final Handler handler = new Handler();
        Timer timer = new Timer();
        TimerTask doAsynchronousTask = new TimerTask() {
            @Override
            public void run() {
                handler.post(new Runnable() {
                    @SuppressWarnings("unchecked")
                    public void run() {
                        try {
                            drawPloyLine();
                        } catch (Exception e) {

                        }
                    }
                });
            }
        };
        timer.schedule(doAsynchronousTask, 0, 5000);

    public void drawPloyLine(){

        for (int e=0 ; e < points.size();e++) {
            options = new PolylineOptions().width(7).color(Color.rgb(0,
                    139, 69)).geodesic(true);
            for (int i = 0; i < points.size(); i++) {
                LatLng point = points.get(i);
                options.add(point);
            }
            line = mGoogleMap.addPolyline(options);
        }
    }

5秒后重复onClick funtkion

2 个答案: