如何使用Jsoup获取值http://api.tivi8k.net/viettel/?cid=154&token=-OWPRmOicPqIKsK97SmOlQ&e=1500542988?
HTML:
xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET", "http://api.tivi8k.net/viettel/?cid=154&token=-OWPRmOicPqIKsK97SmOlQ&e=1500542988", false);
xmlhttp.send();
link = xmlhttp.responseText;
player = new Clappr.Player({
source: link,
parentId: '#player',
width: '100%',
height: "100%",
hideMediaControl: true,
mediacontrol: {
seekbar: "#ffaa56",
buttons: "#ff7f00"
},
autoPlay: true
});
html,
body {
margin: 0;
padding: 0;
background: #000;
;
}
<div style="width: 100%;">
<div id="player"></div>
</div>
<img src="sv2.png" style="position:absolute;top:5px;right:10px" />
Java代码
try {
String userAgent = "Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/54.0.2840.99 Safari/537.36";
Document doc = Jsoup.connect("http://m.xemtvhd.com/vtv1.php").userAgent(userAgent).get();
String url = doc.select("#xmlhttp.open").first().attr("data-source");
System.out.println(url);
} catch (IOException e) {
e.printStackTrace();
}
请支持。感谢支持
答案 0 :(得分:2)
此代码将获取所有<script>
个元素并迭代每个元素,然后它将检查他看起来的那个是你想要的那个: pattern
如果matches
group(1)
(代表捕获组(.*)
,group(0)
是整行),则为Elements script = doc.select("script");
Pattern p = Pattern.compile("xmlhttp.open\\(\"GET\", \"(.*)\", false\\)");
// ^^ is the capturing group
String url = "";
for (Element element : script) {
Matcher m = p.matcher(element.data());
if (m.find()){
url = m.group(1);
}
}
System.out.println(url); //-> http://...542988
:
seenModal