OrderBy Pipe不处理角度4中的对象数组?

时间:2017-07-20 06:06:30

标签: angular angularjs-orderby

我有一个对象数组,我想根据作为对象属性的大小对它们进行排序。对象由{name,size}组成。我想根据大小对元素进行排序。

服务:

search(term: string): Observable<Array<Object>> {
  let apiURL = `${this.apiRoot}?search=${term}`;
  return this.http.get(apiURL)
           .map(res => {
             return res.json().results.map(items => {
               return {name: items.name, population: items.population};
             });
           });
}

成分:

 ngOnInit() { 
  this.myshared.getSaveBtnStatus().subscribe(data => this.isSuccess = data);
    this.searchField = new FormControl();
    this.searchField.valueChanges
    .debounceTime(400)
    .distinctUntilChanged()
    .switchMap(term => this.myservice.search(term))
    .subscribe(value => {
      this.results = value;
      console.log(this.results);
    }
    );

HTML:

<ul class="list-group">
<li class="list-group-item"  *ngFor="let items of results">
{{items.name | orderBy : ['population'] }}
</li>
</ul>

1 个答案:

答案 0 :(得分:2)

Angular 2+没有orderBy管道。但是很容易为你想要的东西建造一个。

这是一个简单的管道实现,以实现你想要的

import { Pipe, PipeTransform } from "@angular/core";

@Pipe({
  name: "orderBy"
})
export class OrderByPipe implements PipeTransform {

  transform(value: any[], property: any, descending?: boolean): any {
    if (!value || value.length) {
      return value;
    }

    value.sort((first: any, second: any): number => {
        return first[property] > second[property] ? 1 : -1;
    });

    if (descending) {
      return value.reverse();
    }

    return value;
  }
}