Question

我有三个构造函数。学校，教师和学生。到目前为止，我的代码中的所有内容都感觉还可以，但我似乎无法在teacher.prototype中获得两个函数来响应。我是Js的新手，我正在努力了解为什么这不响应

//create a constructor for a school that has all teachers and students
function school(principal,teacher,student,classroom,detention){
    this.principal = principal,
    this.teacher = teacher,
    this.student = student;
    this.classroom = [],
    this.detention = []
}
//create a constructor for teachers and students 
//link them all together
function teacher(admin,name){
    this.admin = admin
    this.name = name
    admin = true
//inherit some of the properties of school

}
function student(fname,lname,year,average){
    this.fname = fname,
    this.lname = lname,
    this.year = year,
    this.average = average
}
teacher.prototype = Object.create(school.prototype);
//teacher can send students to class
teacher.prototype.learn = function(student){
    this.classroom.unshift(student)
}
//be able to move students to detention
teacher.prototype.punish = function(student){
    this.detention.unshift(student)
} 


student.prototype = Object.create(teacher.prototype)
student.prototype.fullDetails = function(){
    return this.fname + ' ' + this.lname + " is in " + this.year + 'th' + ' grade and his average is ' + this.average;
}


var mr_feeney = new teacher(true,"Mr.Feeney")
var corey = new student("corey","mathews",10,88)
var shaun = new student("shaun","hunter",10,43)
var top = new student("topanga","lawrence",10,43)

shaun.learn();

Answer 1

在继承原型的类的构造函数中，您需要在当前对象的上下文中调用您继承的构造函数。

e.g。在你的学生构造函数中，你需要这样做

function student(fname,lname,year,average){
    //initialize all the member variables on this object that are created in the teacher constructor by calling teacher.call(this)
    teacher.call(this); 

    this.fname = fname,
    this.lname = lname,
    this.year = year,
    this.average = average
}

调用教师构造函数并初始化教师继承的所有成员变量。

与teacher

继承的school相同

function teacher(admin,name){
    school.call(this);
    this.admin = admin
    this.name = name
    admin = true
}

teacher.prototype = Object.create(school.prototype);

另外，坚持使用约定，为类名使用大写

function student()

应该是

function Student()

所有这一切，你还有一些其他的建筑奇怪 - 如果学生真的继承了与老师相同的方法吗？老师真的应该继承与学校相同的所有属性/方法吗？当您从学生构造函数中调用教师构造函数时，admin和name的默认参数应该是什么？

我无法在我的构造函数中获取原型以获得响应

1 个答案: