Question

说明：

我有一个充满来自传感器网络的数据的目录。我想使用位于文件名中的每个传感器的序列号来创建id向量。。

以下是一些示例文件名：

2017-07-18-32058-aqdata.csv

2017-07-18-32033-aqdata.csv。

每个传感器的序列号位于时间戳之后，例如32058或32033。

以下是我目前正在阅读的数据：

## Load the necessary packages:
if (!require(plyr)){
    install.packages('plyr')
    library(plyr)
}

if (!require(dplyr)){
    install.packages('dplyr')
    library(dplyr)
}

## Define a function to read in a single file:
read.data <- function(file_path){
    df <- read.csv(file_path, header=TRUE, stringsAsFactors=FALSE)
    names(df)<-c("datetime", "co", "co2", "VOC", "RH","ugm3","temp")
    df$datetime <- strptime(df$datetime, format="%Y-%m-%d %H:%M")
    df$datetime <- as.POSIXct(df$datetime, format="%Y-%m-%d %H:%M:%S")
    return(df)
}

## Assign object 'file_path' to my target directory:
file_path <-"~/my_directory/"

## Generate a list of files within this directory:
file_list <- list.files(path = file_path, pattern="\\.csv$", all.files=FALSE, full.names=TRUE, ignore.case=FALSE)

## Apply the data.read function to the list of files:
df_master <- dplyr::ldply(file_list, read.data)
df_master <- plyr::arrange(df_master, datetime)

如何利用每个文件名中的序列号在read.data()函数中创建相应的ID向量？

以下是一些示例数据：

df_example <- structure(list(datetime = structure(c(1497296520, 1497296580, 1497296640, 1497296700, 1497296760, 1497296820), class = c("POSIXct", "POSIXt"), tzone = ""), co = c(0, 0, 0, 0, 0, 0), co2 = c(1118L, 1508L, 836L, 620L, 529L, 498L), VOC = c(62.1353, 59.7594, 59.1831, 57.9592, 56.4335, 53.6528), RH = c(51.45, 52.18, 50.72, 49.71, 49.21, 48.51), ugm3 = c(2.601, 1.061, 1.901, 1.481, 2.501, 3.261), temp = c(72.27, 72.35, 72.45, 72.55, 72.67, 72.77)), .Names = c("datetime", "co", "co2", "VOC", "RH", "ugm3", "temp"), row.names = c(NA, 6L), class = "data.frame")

提前致谢！

Answer 1

这假设您的传感器编号都是5个以上的数字，这有助于避免与日期混淆。使用stringr：

library(stringr)

read.data <- function(file_path){
  df <- read.csv(file_path, header=TRUE, stringsAsFactors=FALSE)
  names(df)<-c("datetime", "co", "co2", "VOC", "RH","ugm3","temp")
  df$datetime <- strptime(df$datetime, format="%Y-%m-%d %H:%M")
  df$datetime <- as.POSIXct(df$datetime, format="%Y-%m-%d %H:%M:%S")

  # New code to pull in sensor number
  df$sensor <- str_extract(file_path, "[0-9]{5,}")
  return(df)
}

根据文件名将ID向量分配给R中的数据帧？

1 个答案: