如何在python中简化此代码？

Question

任务是将3的倍数加到100以下，然后将它们加在一起。

num1 = 0
l = []
while num1 < 100:
    num1 = num1 + 3
    l.append(num1)
# I used this to delete the last element in the list which is 102,
del l[-1]
print l
# sum of all the numbers in l
b = sum(l)
print b

Answer 1

total = 0
for i in range(0,100, 3):
    total += i
print(total)

替代方案，单行：

answer = sum(range(0, 100, 3))

Answer 2

你可以试试这个：

sum(range(0, 100, 3))

Answer 3

通过高斯和，

total = 3 * (100 // 3) * (100 // 3 + 1) // 2