所以我正在编写一个程序来检查.txt文件的每一行是否是回文,
import System.IO
main :: IO()
main = do {
content <- readFile "palindrom.txt";
print content;
print (lines content);
singleWord (head (lines content));
return ();
}
palindrom :: [Char] -> Bool
palindrom a = a == reverse a
singleWord :: [Char] -> IO()
singleWord a = do {
print (length a);
print (show (palindrom a));
}
但我需要在整个列表中运行singleWord (head (lines content))
而不是singleWord
。
问题在于map
或正常列表理解我总是得到大量不同的错误,与lines content
(应该是一个字符串或IO字符串数组)有关,显然总是类型我不想要(我已经尝试过永久性地处理类型声明,但它仍然是错误的类型,或者是正确的类型,但是在一个额外的数组层或其他什么)。
我的最后一次尝试是通过递归来遍历数组,只需要一些额外的代码:
walkthrough [] = []
walkthrough x = do { singleWord head x; walkthrough (tail x) }
无论如何我无法正确地进行类型转换。
它应该替换singleWord (head (lines content))
中的main
,如果我尝试使用类型分类,例如
walkthrough :: [[Char]] -> [[Char]]
walkthrough [] = ["Hi"]
walkthrough x = do { singleWord head x; walkthrough (tail x) }
我得到了
Couldn't match type `IO' with `[]'
Expected type: [()]
Actual type: IO ()
或其他一些不合适的东西。
答案 0 :(得分:4)
您正在寻找名为mapM_
的函数。
main :: IO ()
main = do {
content <- readFile "palindrom.txt";
mapM_ singleWord (lines content);
};
palindrome :: [Char] -> Bool
palindrome a = (a == reverse a)
singleWord :: [Char] -> IO()
singleWord a = do {
let {
adverb = (if palindrome a then " " else " not ");
};
putStrLn (a ++ " is" ++ adverb ++ "a palindrome.");
};
答案 1 :(得分:3)
应该
walkthrough [] = return () -- this is the final action
walkthrough x = do { singleWord (head x) -- here you missed the parens
; walkthrough (tail x) }
或更好,
walkthrough [] = return ()
walkthrough (x:xs) = do { singleWord x -- can't make that mistake now!
; walkthrough xs}
并在主walkthrough (lines content)
区块中将其称为do
。
正如其他人所指出的那样,walkthrough
与mapM_ singleWord
相同。
你也可以用列表理解来编写它,
walkthrough xs = sequence_ [ singleWord x | x <- xs]
sequence_ :: Monad m => [m a] -> m ()
将操作列表转换为一系列操作,放弃其结果并最终生成()
:sequence_ = foldr (>>) (return ())
。 sequence_ (map f xs)
=== mapM_ f xs
,所以最终都会绑定。
答案 2 :(得分:2)
使用mapM_ singleWord (lines content)
。为简单起见,请将mapM_
视为。
mapM_ :: (a -> IO ()) -> [a] -> IO ()