Question

我有这样的价值：

Supoose我有一个字符串：

s = "server ('m1.labs.teradata.com') username ('u\'se)r_*5') password('uer 5')  dbname ('default')";

我需要提取

token1：'m1.labs.teradata.com'
token2：'u\'se)r_*5'
token3：'uer 5'

我在cpp中使用以下正则表达式：

regex re("(\'[!-~]+\')"); 

sregex_token_iterator i(s.begin(), s.end(), re, 0);
sregex_token_iterator j;

unsigned count = 0;
while(i != j)
  {
    cout << "the token is"<<"   "<<*i++<< endl;
    count++;
  }
cout << "There were " << count << " tokens found." << endl;

return 0;

Answer 1

如果您不希望字符串中包含符号'，则'[^']+'会匹配您所需的内容：

regex re("'[^']+'");

live example 结果：

the token is   'FooBar'
the token is   'Another Value'
There were 2 tokens found.

如果您不需要单引号作为匹配更改代码的一部分：

regex re("'([^']+)'");

sregex_token_iterator i(s.begin(), s.end(), re, {1});

another live example

the token is   FooBar
the token is   Another Value
There were 2 tokens found.

Answer 2

此字符串的正确正则表达式为

(?:'(.+?)(?<!\\)')

https://regex101.com/r/IpzB80/1

正则表达式使用boost令牌迭代器在单引号和括号之间提取值

2 个答案: