Question

我有一个包含creditAmount和terminal_ID字段的表格，其中我的值为＆gt; 0且某些值为＆lt; 0.我想计算> 0的行和每条记录的terminal_id。

我试过了：

SELECT terminal_ID, COUNT(to_number(credit_amount)) AS count 
FROM isevaHarmsReports1 where to_number(credit_amount) > 0 group by  terminal_ID;

如果我执行上述查询，它只给出credit_amount＆gt;用户的count和terminal_ID。 0但不是哪个＆lt; 0

if credit amount is < 0 I want only terminal_id
if credit amount is > 0 I want only terminal_id and count

如何根据条件计算行？

Answer 1

试试这个

select terminal_id, 
       count(case when credit_amount > 0 then 1 end) as count_gt0,  
       count(case when credit_amount < 0 then 1 end) as count_lt0 
from your_table
group by terminal_id

如果credit_amount在其他case范围内，1表达式会null。聚合函数count不考虑空值。

Answer 2

你可以尝试一下：

SELECT terminal_id, COUNT(*)
   FROM isevaHarmsReports1
  WHERE TO_NUMBER(creditAmount) > 0
  GROUP BY terminal_id
UNION
SELECT terminal_id, NULL
   FROM isevaHarmsReports1
  WHERE TO_NUMBER(creditAmount) < 0
  GROUP BY terminal_id

是否有可能将条件置于oracle中的count函数内？

2 个答案: