我想删除字符串中的字母:
select CAST(dstring as number), * from myTable
dstring可以是M-St2,DE2,M12,
结果应为2,2,12
由于
答案 0 :(得分:0)
替换列中的数字。例如' John12'删除' 12'从专栏然后返回' John',然后替换' John'。你可以得到' 12'
SELECT
REPLACE(dstring, REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE (
REPLACE( REPLACE( REPLACE( REPLACE(dstring ,'0','')
,'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9',''), '')
FROM myTable;
答案 1 :(得分:0)
似乎没有这样的功能。
我真正的问题如下:我想通过dstring正确地订购我的表。
我试过这段代码:
select dstring from myTable order by dstring
并得到以下内容: 圣 ST1 ST10 ST11 ST12 ST2 ST20 ST21 ST3
但我希望它像那样
ST ST1 ST2 ST3 ST10 ST11 ST12 ST20 ST21
有谁知道如何解决这个问题? 谢谢!
答案 2 :(得分:0)
钉了它。...这将删除a-z和A-Z,将所有其他字符留在后面...
UPDATE some_table SET some_field = REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE(some_field,'a','') ,'b','') ,'c','') ,'d','') ,'e','') ,'f','') ,'g','') ,'h','') ,'i','') ,'j','') ,'k','') ,'l','') ,'m','') ,'n','') ,'o','') ,'p','') ,'q','') ,'r','') ,'s','') ,'t','') ,'u','') ,'v','') ,'w','') ,'x','') ,'y','') ,'z','') ,'A','') ,'B','') ,'C','') ,'D','') ,'E','') ,'F','') ,'G','') ,'H','') ,'I','') ,'J','') ,'K','') ,'L','') ,'M','') ,'N','') ,'O','') ,'P','') ,'Q','') ,'R','') ,'S','') ,'T','') ,'U','') ,'V','') ,'W','') ,'X','') ,'Y','') ,'Z','');
这是我的PHP生成该代码(在$ to_remove字符串中添加您需要的其他任何字符:
$to_remove = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
$removals = str_split($to_remove,1);
$stmt = "some_field";
foreach($removals as $x) {
$stmt = " REPLACE(".$stmt.",'".$x."','') ";
}
$stmt = "update some_table set some_field = ".$stmt." ";
echo($stmt);
答案 3 :(得分:-1)
尝试执行此代码,它可能对您有所帮助。
dstring可以是M-St2,DE2,M12,
结果应为2,2,12
仅显示数值。
将NumericOnly(dstring)作为myTable中的数字