Question

休息框架有问题：使用视图和路由器构建api。

我希望api按照以下方式将用户的帖子序列化： / api / users / 用户ID / posts / 页面，但路由器不能忍受它。它建议我使用regexp模式：

logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s : %(message)s') logging.getLogger("requests").setLevel(logging.WARNING) logging.getLogger("urllib3").setLevel(logging.WARNING)

^api/ ^ ^users/posts\.(?P<format>[a-z0-9]+)/?$ [name='user-posts']

有任何想法如何正确地推动这项工作？提前谢谢！

Answer 1

的观点：

@detail_route()
def posts(self, request, pk, page):
    user = self.get_object()
    post_set = Post.objects.filter(owner=user)
    paginator = Paginator(post_set, 16)
    serializer = PostSerializer(paginator.page(page), many=True, context={'request': request})
    return Response(serializer.data)

网址：

router = DefaultRouter()
router.register(r'posts', views.PostViewSet)
router.register(r'users', views.UserViewSet)
user_posts = views.UserViewSet.as_view({
    'get': 'posts'
})

urlpatterns = [
    url(r'^', include(router.urls)),
    url(r'^users/(?P<pk>\w+)/posts/(?P<page>[0-9]+)', user_posts),
]

Answer 2

class UserViewSet(viewsets.ReadOnlyModelViewSet):
    queryset = User.objects.all()
    serializer_class = UserSerializer

    @detail_route()
    def posts(self, request, pk):
        user = self.get_object()
        post_set = Post.objects.filter(owner=user)
        paginator = Paginator(post_set, 16)
        page= request.query_params.get('page', 1)
        serializer = PostSerializer(paginator.page(page), many=True, context={'request': request})
        return Response(serializer.data)

urls.py

router.register('user', UserViewSet)

ViewSet和Router在休息框架中

2 个答案: