Php代码，为foreach循环添加一个条件

Question

如何使此代码有效？ TY！

$site = '1'

    $mysites = array('1', '2', '3', '4', '5', '6');
            foreach($mysites as $mysite) 
            {
            echo $mysites;  **but not the site with value 1**
            }

Answer 1

一个简单的if就足够了：

$site = '1';

$mysites = array('1', '2', '3', '4', '5', '6');
foreach($mysites as $mysite) 
{
    if ( $mysite !== '1' )
    {
        echo $mysite;
    }
}

或者如果您不想检查$site变量：

$site = '1';

$mysites = array('1', '2', '3', '4', '5', '6');
foreach($mysites as $mysite) 
{
    if ( $mysite !== $site )
    {
        echo $mysite;
    }
}

Answer 2

只需使用if声明：

foreach($mysites as $mysite) {
    if ($mysite !== $site) {
        echo $mysite;
    }
}

Answer 3

$site = '1'

    $mysites = array('1', '2', '3', '4', '5', '6');

    foreach($mysites as $mysite) {
        if ($mysite == $site) { continue; }

        // ...your code here...
    }

Answer 4

你可以这样做：

$mysites = array('1', '2', '3', '4', '5', '6');
        foreach($mysites as $mysite) 
        {
if($mysite != 1){
        echo $mysite;
}
        }