从render方法渲染不同组件需要什么实现。正如您在下面看到的,这个想法是Survey component
接收一个包含不同组件名称的数组(可以是Input,CheckList,Dropdown,File)。数组传递为Survey Component
的属性,根据单击的按钮正确生成,但在渲染不同组件时不起作用。我使用JsComplete来测试它。
const Dropdown = () =>{
return(
<div>
<select>
<option value="initial" selected>Select...</option>
<option value="Option ">Option 1</option>
<option value="Option ">Option 2</option>
</select>
</div>
)
}
const Checklist = () =>{
return(
<div>
<h4>Question name</h4>
<label>
Option 1:
<input
name="pl"
type="checkbox" />
</label>
<label>
Option 2:
<input
name="tz"
type="checkbox" />
</label>
</div>
)
}
const Input = () =>{
return(
<div>
<label>
Question name:
<input
name="input"
type="text" />
</label>
</div>
)
}
const File = () =>{
return(
<div>
<label>
Upload:
<input
name="file"
type="file" />
</label>
</div>
)
}
class Survey extends React.Component {
constructor(props){
super(props);
}
render(){
var ChildName ;
for (var i = 0; i < this.props.components.length; i++) {
log("Log:" + this.props.components[i]);
ChildName = this.props.components[i];
return <ChildName />;
}
return (
false
)
}
}
class Form extends React.Component {
handleSubmit = (name) => {
this.props.onSubmit(name);
};
render() {
return (
<div id="components">
<button onClick={()=>this.handleSubmit("Input")} name="Input">Input</button>
<button onClick={()=>this.handleSubmit("Checklist")} name="Checklist">Checkbox</button>
<button onClick={()=>this.handleSubmit("Dropdown")} name="Dropdown">Dropdown</button>
<button onClick={()=>this.handleSubmit("File")} name="File">File</button>
<div id="new-question">
</div>
</div>
)
}
}
class App extends React.Component {
state = {
components: []
};
addNewElement = (element) => {
this.setState(prevState => ({
components: prevState.components.concat(element)
}));
};
render() {
return (
<div>
<Form onSubmit={this.addNewElement} />
<Survey components={this.state.components} />
</div>
);
}
}
ReactDOM.render(<App />, mountNode);
答案 0 :(得分:1)
试试这个。不要在handleSubmit方法中传递字符串。而是像这样传递组件本身:
class Form extends React.Component {
handleSubmit = (name) => {
this.props.onSubmit(name);
};
render() {
return (
<div id="components">
<button onClick={()=>this.handleSubmit(Input)} name="Input">Input</button>
<button onClick={()=>this.handleSubmit(Checklist)} name="Checklist">Checkbox</button>
<button onClick={()=>this.handleSubmit(Dropdown)} name="Dropdown">Dropdown</button>
<button onClick={()=>this.handleSubmit(File)} name="File">File</button>
<div id="new-question">
</div>
</div>
)
}
}
同样在您的调查组件中返回这样的元素
class Survey extends React.Component {
constructor(props) {
super(props);
}
render() {
if (this.props.components.length === 0) {
return null;
}
const renderCommpos = this.props.components.map((Elem, index) => {
return <Elem key={index} />
});
return (
<div>
{renderCommpos}
</div>
);
}
}
另请注意地图功能中的Elem
。当涉及到反应组件时,jsx需要首字母大写。所以你在Elem
所保留的变量并不重要,你应该始终保留首字母大写。
答案 1 :(得分:0)
调查组件的渲染方法应如下所示:
render(){
const { components } = this.props;
return (
<div>
{
components.map((c, index) => {
return (
<div key={`one-of-components-${index}`}>
{c}
</div>
);
})
}
</div>
);
}
现在它将返回道具中的所有组件。
答案 2 :(得分:0)
试试这个。
const Survey = ({ components }) => {
const Components = components.map(
( component, index ) => {
return (
<div key={ index }>
{ component }
</div>
);
}
);
return (
<div>
{ Components }
</div>
);
};
在for循环中,您将从第一个组件的函数返回。将它们添加到数组,然后返回该数组。另外,我在这里使用了一个功能无状态组件。我没有看到课程开销的必要性。