Question

我是java的新手，目前正在攻读本科编程课程。我已经获得了一项任务，要求我创建和加密类，然后是测试人员类。在tester类中，我将创建加密类的两个对象：一个使用默认构造函数，另一个使用参数化构造函数，使用两个扫描程序输入作为参数（密码和密钥）。这就是我遇到的困难。我不认为我这样做是正确的。这是代码。我编译它时收到的错误是“不兼容的类型，String不能转换为int”。我感谢任何可以帮助我的人。

public class Encryption
{
   private int key; 
   private String encryptedPassword;
   Scanner scan = new Scanner(System.in);

   public Encryption()
   {
      key = 0;
      encryptedPassword = "";
   }

   public Encryption(int key, String password)
   {
      this.key = key;
      password = password;   
      setPassword(password);
   }

   public void encrypt(String password)
   {
      char ch;
      for(int i=0; i<password.length(); i++){
      ch = password.charAt(i);

      if (ch >= '!' && ch <= 'z'){
         ch = (char)(ch + key);

         if (ch  > 'z'){
            ch = (char)(ch - 'z' + '!' - 1);}

         else if (ch < '!'){
              ch = (char)(ch +'z' - '!' +1);}
              encryptedPassword = password + ch;             
         }
      }
   }

   public boolean isValidPassword (String password)
   {
      encrypt(password);
      if (password.equals(encryptedPassword))
      return true;
      else
      return false;
   }

   public String getEncryptedPassword()
   {
      return encryptedPassword;
   }

   public void setPassword(String password)
   {
      encrypt(password);
   }

   public int getKey()
   {
      return key;
   }

   public String toString()
   {
      return "The encrypted password is " + getEncryptedPassword() + ". " +  "The key used to generate this password is " + getKey() + ".";            
   }
}

这是测试人员类代码。

import java.util.Scanner;

public class EncryptionTester
{   
   public static void main(String[] args)
   {
      Scanner scan = new Scanner(System.in);
      System.out.println("Enter a password.");
      String password = scan.next();

      while (password.length() < 8)
      {      
          System.out.println("The password must be at least 8 characters long. Your password is only " + password.length() + " characters long.");
          System.out.println("Enter a password.");
          password = scan.next();
      }

      System.out.println("Enter a number between 1 and 10.");         
      int key = scan.nextInt();

      while (key < 1 || key > 10)
      {
         System.out.println("The key must be between 1 and 10. You entered " + key);
         System.out.println("Enter a number between 1 and 10");
         key = scan.nextInt();
      }

      Encryption defaultEncryption = new Encryption();
      Encryption argEncryption = new Encryption(password, key);
    }

Answer 1

您正在将构造函数调用为

new Encryption(password, key);

声明时

public Encryption(int key, String password)

您需要按参数列表中指定的顺序传入参数。尝试

new Encryption(key, password);

在java中使用scanner输入作为构造函数参数

1 个答案: