Question

我想根据特定条件生成分组JSON元素的列表，但我无法使循环工作。该函数应该组成12瓶并返回一个JSON列表。因此，在此示例中，函数应提取3个第一项，然后再次运行以提取剩余的项。但我永远在循环......提前谢谢你，

var data = {
    "order": [
        { "product": "MAXIMUS", "quantity": "3" },
        { "product": "COLECCION", "quantity": "3" },
        { "product": "CABERNET FRANC", "quantity": "6" },
        { "product": "CHARDONNAY", "quantity": "6" },
        { "product": "SAUVIGNON BLANC", "quantity": "6" }
    ]
};

var qtd = data.order;
var size = qtd.length;
var addline = '';
var add = '';
var total = 0;
var i = 0;
var a = 0;
var c = '';

function MakeList(i, add) {
    for (i < 0; total < 12; i++) {
        total += parseInt(qtd[i].quantity);
        addline = addline + '{' + '"quantity": "' + qtd[i].quantity + ' units"},';
        i = i++;
        add = '{"Box of 12":[' + addline.slice(0, -1) + "]}";
    }
    return [i, add];
}

function BuildLabels(i, add) {
    for (i < 0; c = "true"; i++) {
        c = a[0] < size;
        a += MakeList(i, add);
        i = i++;
    }
    return a;
}

var results = BuildLabels(i, add);
output = { id: 3, results };

Answer 1

for (i < 0; c = "true"; i++)

这里发生了一些奇怪的事情。您没有为要停止的周期设置任何条件，只需将值“true”赋给c即可。尝试使用==代替=;初始化看起来很奇怪 - 将i设置为0。显然，它会使整个事情起作用（至少循环会在某个时刻停止），但最后我得到变量results等于0。还有其他错误/奇怪的东西。可能，你想要实现这样的目标：

var data = {
    "order": [
        { "product": "MAXIMUS", "quantity": "3" },
        { "product": "COLECCION", "quantity": "3" },
        { "product": "CABERNET FRANC", "quantity": "6" },
        { "product": "CHARDONNAY", "quantity": "6" },
        { "product": "SAUVIGNON BLANC", "quantity": "6" }
    ]
};

function MakeList(data) {
    var selected = [], bottlesNum = 0;
    for (var i = 0; bottlesNum < 12; i++) {
        selected.push(data.order[i]);
        bottlesNum += parseInt(data.order[i].quantity);
    }
    return selected;
}

    var results = MakeList(data);
    // now it is a JS object:
    console.log({ id: 3, results: results });
    // if you want it to be a JSON string, use JSON.stringify():
    console.log(JSON.stringify({ id: 3, results: results }));

检查出来。

<强>更新

var data = {
    "order": [
        { "product": "MAXIMUS", "quantity": "3" },
        { "product": "COLECCION", "quantity": "3" },
        { "product": "CABERNET FRANC", "quantity": "6" },
        { "product": "CHARDONNAY", "quantity": "6" },
        { "product": "SAUVIGNON BLANC", "quantity": "6" }
    ]
};

function makeGroup(data, max) {
    var selected = [], bottlesNum = 0;
    while(data.order.length) {
      if(bottlesNum + +data.order[0].quantity > max) break;
        var order = data.order.shift();
        bottlesNum += +order.quantity;  // casting to Number
        selected.push(order);
    }
    return selected;
}

function splitOrder(data, max) {
 while(data.order.length) {
    var results = makeGroup(data, max);
    if(!results.length) {
      console.log("Error: a product's quantity is greater than max. size of the group. Try to increase max. size of the group."); 
      break;
    }
    console.log({ results: results });
 }
}
// 2nd argument - max. size of the group. In case of 12 there will be 2 groups - of 3, 3, 6 and 6, 6 bottles
splitOrder(data, 12);

// Also notice that if max. size of the group is a changing value and can be set somehow to, lets say, 4 which is fewer than number of some products (6) in our order. So, it is impossible to complete such a task without taking some additional steps to handle this situation. For example, we could filter our data beforehand to exclude products with numbars greater than 4 and then form groups based on the rest of the data. Or we can treat products with number equal to 6 as if they satisfy our constraint etc.

在函数之间循环并存储结果

1 个答案: