Question

我有以下两个功能：

>>> def spam():
...     raise ValueError('hello')
...
>>> def catch():
...     try:
...         spam()
...     except ValueError:
...         raise ValueError('test')

尝试捕获第二个ValueError异常可以正常工作并打印异常的错误消息：

>>> try:
...     catch()
... except ValueError as e:
...     print(e)
...
test

是否有办法访问原始异常的错误消息（即'hello'）？我知道我可以打印完整的追溯：

>>> try:
...     catch()
... except ValueError as e:
...     import traceback
...     print(traceback.format_exc())
...
Traceback (most recent call last):
  File "<stdin>", line 3, in catch
  File "<stdin>", line 2, in spam
ValueError: hello

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "<stdin>", line 5, in catch
ValueError: test

但我并不想完全解析该字符串中的hello。有没有办法访问异常列表及其各自的消息，我只能从中获取第一个消息？

Answer 1

想出来：原始例外可通过e.__cause__获得。

Python：访问原始异常的异常消息

1 个答案: