Question

我有两个不同控制器/型号的登录。 1 - 对于contender_user 2 - 对于enterprise_user。虽然它们在文件中与企业用户看起来完全相同但我无法达到enterprise_user的id

没有错误的文件：

namespace App\Http\Controllers\contender_user;

use Illuminate\Http\Request;
use Illuminate\Support\Facades\DB;
use Illuminate\Support\Facades\Session;
use Illuminate\Support\ServiceProvider;

use App\Http\Requests;
use App\Http\Controllers\Controller;
use App\Models\contender_user;
use Illuminate\Support\Facades\Auth;


class contender_userController extends Controller
{


    public function applications_contender_user_show () {
       return view('contender_user/applications');
    }


    public function home_show () {

       $id = Auth::user()->id;
       $contender_user = new contender_user\contender_userModel();

       $results = $contender_user->get_user_all($id);


        return view('contender_user/home', array
            (
               'name'    =>  $results[0]->name,
               'email'  =>  $results[0]->email,
               'created_at'  =>  $results[0]->created_at
            ));

    }
}

错误的文件：行：$ id = Auth :: user（） - ＆gt; id; 错误：尝试获取非对象的属性

namespace App\Http\Controllers\enterprise_user;


use Illuminate\Http\Request;
use Illuminate\Support\Facades\DB;
use Illuminate\Support\Facades\Session;
use Illuminate\Support\ServiceProvider;
use Illuminate\Support\Facades\Auth;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use App\Models\enterprise_user;

class enterprise_userController extends Controller
{
public function applications_show () {
    return view('enterprise_user/applications');
}

public function home_show () {

    $id = Auth::user()->id;
    $enterprise_user = new enterprise_user\enterprise_userModel();

    $results = $enterprise_user->get_user_all($id);


    return view('enterprise_user/home', array
        (
            'name'    =>  $results[0]->name,
            'email'  =>  $results[0]->email,
            'created_at'  =>  $results[0]->created_at
        )
    );

}

当我复制工作文件时，它仍然出现错误信息：（

请帮助

Answer 1

对于Laravel 5.2，您可以通过以下方式获得经过身份验证的用户：

Auth::guard('user')->user()->id //guard can be user,admin etc depend on your settings

Answer 2

试试这个

public function home_show () {
   if($id){
     $enterprise_user = new enterprise_user\enterprise_userModel();

    $results = $enterprise_user->get_user_all($id);


    return view('enterprise_user/home', array
        (
            'name'    =>  $results[0]->name,
            'email'  =>  $results[0]->email,
            'created_at'  =>  $results[0]->created_at
        )
    );
}
else{
    ///what ever you want to do
}

}

Auth :: user（） - ＆gt; id不会工作Laravel 5.2 /试图获取非对象的属性

2 个答案: