Question

我有应用程序，我需要在特定时间打开对话框，我在互联网上搜索但是它不起作用，例如，我需要每天8:00打开对话框，但是当应用程序是关闭???

这是我在互联网上找到的东西

   AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
    alarmManager.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP,
            SystemClock.elapsedRealtime(),
            2*60*1000,
            pendingIntent);

Answer 1

尝试上面的代码，它可能有助于使用通知

MainActivity.java

      package com.example;

import java.util.Calendar;
import android.app.Activity;
import android.app.AlarmManager;
import android.app.PendingIntent;
import android.content.Intent;
import android.os.Bundle;


public class MainActivity extends Activity 
{

    private PendingIntent pendingIntent;

    @Override
    public void onCreate(Bundle savedInstanceState) 
    {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Calendar calendar = Calendar.getInstance();


        //set notification for date --> 8th January 2015 at 9:06:00 PM , here month starts from 0 like 0 to Jan, 1 to Feb...
        calendar.set(Calendar.MONTH, 6);
        calendar.set(Calendar.YEAR, 2017);
        calendar.set(Calendar.DAY_OF_MONTH, 18);

        calendar.set(Calendar.HOUR_OF_DAY, 18);
        calendar.set(Calendar.MINUTE, 22);
        calendar.set(Calendar.SECOND, 0);
        calendar.set(Calendar.AM_PM,Calendar.PM);

        Intent myIntent = new Intent(MainActivity.this, MyReceiver.class);
        pendingIntent = PendingIntent.getBroadcast(MainActivity.this, 0, myIntent,0);

        AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
        alarmManager.set(AlarmManager.RTC, calendar.getTimeInMillis(), pendingIntent);

    } //end onCreate

}

MyReciever.java

     package com.example;

import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.util.Log;

public class MyReceiver extends BroadcastReceiver
{

    @Override
    public void onReceive(Context context, Intent intent)
    {
        /*Intent service1 = new Intent(context, MyAlarmService.class);
         context.startService(service1);*/
        Log.i("App", "called receiver method");
        try{
            Utils.generateNotification(context);
        }catch(Exception e){
            e.printStackTrace();
        }
    }

}

现在终于创建了utils.java

       package com.example;

import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.content.Context;
import android.content.Intent;

public class Utils {

    public static NotificationManager mManager;

    @SuppressWarnings("static-access")
    public static void generateNotification(Context context){ 

     Notification.Builder builder = new Notification.Builder(context);
    Intent notificationIntent = new Intent(context,MainActivity.class);
    PendingIntent pendingIntent = PendingIntent.getActivity(context, 0,notificationIntent, 0);
    builder.setSmallIcon(R.drawable. notification_template_icon_bg)
            .setContentTitle("This is a test message!")
            .setContentIntent(pendingIntent);
    NotificationManager notificationManager = (NotificationManager) context.getSystemService(NOTIFICATION_SERVICE);
    Notification notification = builder.getNotification();
    notificationManager.notify(R.drawable.notification_template_icon_bg, notification);
    }
}

您的清单文件如上所述

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.example"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk
        android:minSdkVersion="8"
        android:targetSdkVersion="10" />


    <uses-permission android:name="android.permission.WAKE_LOCK" />

    <application
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >
        <activity
            android:name="com.example.MainActivity"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

        <receiver android:name=".MyReceiver"/>


    </application>

</manifest>

更多结帐this link of github repo

Answer 2

我建议您不要这样做（这违反了Android设计和UI指南）。通知是完成您正在做的事情的首选方式

如果您真的想要显示对话框，我建议您只使用Dialog主题活动。这样您就不必启动单独的dialog。创建Activity as Dialog Theme并从服务启动该活动。

1）为对话活动创建样式

<style name="Theme.CustomTranslucent" parent="android:style/Theme.Translucent">
        <item name="android:backgroundDimEnabled">true</item>
        <item name="android:backgroundDimAmount">0.5</item>
        <item name="android:windowNoTitle">true</item>
        <item name="android:windowAnimationStyle">@android:style/Animation.Dialog</item>
        <item name="android:background">@android:color/transparent</item>
        </style>

2）在manifest.xml

中注册您的活动

            <activity
            android:name=".activity.NotificationActivity"
            android:theme="@style/Theme.CustomTranslucent">

在特定时间显示对话框，以便应用程序正在运行或关闭

2 个答案: