Question

我使用位于here

的DateTimePicker脚本为咨询协议列表创建了一个应用程序

直到现在一切正常，现在，我想要的是如何检索当天名称的数据，然后更改咨询服务时钟（radiobutton）列表。

例如：周一至周四有3种选择：

08 - 10
10 - 12
13 - 15

周五：

09 - 10
10-11.30
13.30 - 15

遵循现有脚本

<div id="datedays">
    <div class="controls input-append date form_date" data-date="" data-date-format="dd-mm-yyyy" data-link-field="dtp_input1" data-link-format="yyyy-mm-dd">
        <input class="date" size="16" type="text" value="" readonly>
        <span class="add-on"><i class="icon-remove"></i></span>
        <span class="add-on"><i class="icon-th"></i></span>
    </div>
    <input name="tanggal" type="hidden" id="dtp_input1" value="" />
    <input name="harinya" type="hidden" id="daynames" value="" />
</div>
<div id="hourpick">
    <input type="radio" name="hours" value="1"> 09.00 - 10.00<br/>
    <input type="radio" name="hours" value="2"> 10.00 - 12.00<br/>
    <input type="radio" name="hours" value="3"> 13.00 - 15.00<br/>
</div>
<script type="text/javascript">
    $('.form_date').datetimepicker({
        language:  'id',
        startDate:'<?php echo date('Y-m-d', strtotime($date .' +2 day'));?>',
        weekStart: 1,
        daysOfWeekDisabled:[0,6],
        todayBtn:  0,
        autoclose: 1,
        todayHighlight: 1,
        startView: 2,
        minView: 2,
        forceParse: 0
    });
</script>

更新

我发现在bootstrap-datetimepicker.en.js（包含在DateTimePicker下载包中）这段代码

;(function($){
    $.fn.datetimepicker.dates['id'] = {
        days: ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"],
        daysShort: ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"],
        daysMin: ["Sn", "Mn", "Tu", "Wd", "Th", "Fr", "Sa", "Sn"],
        months: ["January", "February", "March", "April", "May", "Juni", "July", "Augusts", "September", "October", "November", "December"],
        monthsShort: ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"],
        today: "Today",
        suffix: [],
        meridiem: [],
        weekStart: 1,
        format: "dd/mm/yyyy hh:ii:ss"
    };
}(jQuery));

但我仍然不知道如何获得那天的价值

Answer 1

您可以使用日期格式来获取星期几

更多信息here。寻找“w”

$dayOfTheWeek = intval(date("w"));

if($dayOfTheWeek >= 1 && $dayOfTheWeek <= 4) {
    //Monday to Thursday
} elseif($dayOfTheWeek <= 5) {
    //Friday
} else {
    //other days
}

使用DateTimePicker获取日期名称并更改服务小时列表

1 个答案: