Question

我正在为学校制作棋盘游戏，我希望能够找到他们所拥有的地点编号的索引，并用他们的计数器替换棋盘上的数字（＆＃34; x＆＃34;或＆＃34; y＆＃34;）。

board = [
    ["43","44","45","46","47","48","49"],
    ["42","41","40","39","38","37","36"],
    ["29","30","31","32","33","34","35"],
    ["28","27","26","25","24","23","22"],
    ["15","16","17","18","19","20","21"],
    ["14","13","12","11","10","9 ","8 "],
    ["1 ","2 ","3 ","4 ","5 ","6 ","7 "]

    ]

for line in board:
    print (line)
roll = input("Player " + player + " press enter to roll the dice")
print ("Your counter is",counter)

if roll != "blablabla":
    die1 = random.randint(1,6)
    die2 = random.randint(1,6)
    dice = die1 + die2
    print (die1)
    print (die2)
    print ("You rolled",dice)

if player == "one":
    place1 =(place1+dice)
    print ("P1's place is",place1)
else:
    place2 =(place2+dice)
    print ("P2's place is",place2)

如何找到＆＃34; place1＆＃34;的字符串版本？或＆＃34; place2＆＃34;在董事会中用其他东西替换该指数？

谢谢！

Answer 1

您需要遍历主列表，然后可以使用list.index()查找子列表索引，例如：

def index_2d(data, search):
    for i, e in enumerate(data):
        try:
            return i, e.index(search)
        except ValueError:
            pass
    raise ValueError("{} is not in list".format(repr(search)))

它的行为与list.index()完全相同，但对于2D数组，所以在你的情况下：

position = index_2d(board, "18")  # (4, 3)
print(board[position[0]][position[1]])  # 18

position = index_2d(board, "181")  # ValueError: '181' is not in list

Answer 2

ind = np.where(np.array(board) == str(place1))将返回board数组中所有元素的索引等于place。要替换这些值，请执行以下操作：board[ind] = newval。

基本上，

import numpy as np
ind = np.where(np.array(board) == str(place1))
board[ind] = newval

Answer 3

我添加了额外的下线。 Array采用整数值，但不是元组/列表。那么，代码片段中的下面一行已经由@zwer给出了。感谢@zwer。

board[position[0]][position[1]] = 'Replaced'



def index_2d(data, search):
    for i, e in enumerate(data):
        try:
            return i, e.index(search)
        except ValueError:
            pass
    raise ValueError("{} is not in list".format(repr(search)))


board = [
    ["43","44","45","46","47","48","49"],
    ["42","41","40","39","38","37","36"],
    ["29","30","31","32","33","34","35"],
    ["28","27","26","25","24","23","22"],
    ["15","16","17","18","19","20","21"],
    ["14","13","12","11","10","9 ","8 "],
    ["1 ","2 ","3 ","4 ","5 ","6 ","7 "]

    ]

position = index_2d(board, "21")
board[position[0]][position[1]] = 'Replaced'
print("{}".format(board))

输出就像是，注意“替换”了。

[
['43', '44', '45', '46', '47', '48', '49'], 
['42', '41', '40', '39', '38', '37', '36'], 
['29', '30', '31', '32', '33', '34', '35'], 
['28', '27', '26', '25', '24', '23', '22'], 
['15', '16', '17', '18', '19', '20', 'Replaced'], 
['14', '13', '12', '11', '10', '9 ', '8 '], 
['1 ', '2 ', '3 ', '4 ', '5 ', '6 ', '7 ']
]

如何在python中找到2D数组中的值？

3 个答案: