Question

我是java android开发的初学者，我创造了一个tic tac toe游戏。我已经完成了游戏的代码。但我对游戏的胜利条件感到困惑，因为我只是在网上向教练学习。这是我对游戏毫无头绪的具体代码

//winning condition
//for(int [] winningPosition : winningPositions){
        if(gameState[winningPosition[0]] == gameState[winningPosition[1]] &&
                gameState[winningPosition[1]] == gameState[winningPosition[2]] &&
                gameState[winningPosition[0]] != 2)

这是代码。（我没有发布整个代码，因为我只想展示相关代码，以帮助您理解我想要问的内容）

public class MainActivity extends AppCompatActivity {

//0 = yellow , 1 = red;
int activePlayer = 0;
boolean gameIsActive = true;
//2 mean unplayed
int [] gameState = {2,2,2,2,2,2,2,2,2};
int [][] winningPositions = {{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};

public void dropIn (View view) {

    ImageView counter = (ImageView) view;


    int tappedCounter = Integer.parseInt(counter.getTag().toString());
    if (gameState[tappedCounter] == 2 && gameIsActive) {

        gameState[tappedCounter] = activePlayer;


        counter.setTranslationY(-1000f);
        if (activePlayer == 0) {
            counter.setImageResource(R.drawable.yellow);
            activePlayer = 1;
        } else {

            counter.setImageResource(R.drawable.red);
            activePlayer = 0;
        }

        counter.animate().translationYBy(1000f).rotation(360).setDuration(300);
        for(int []winningPosition : winningPositions){

            if(gameState[winningPosition[0]] == gameState[winningPosition[1]] &&
                    gameState[winningPosition[1]] == gameState[winningPosition[2]] &&
                    gameState[winningPosition[0]] != 2)
                            {
                                //Someone has won!
                                gameIsActive = false;
                                String winner = "Red";
                                if(gameState[winningPosition[0]] == 0){

                                 winner = "Yellow";
                            }
                                LinearLayout layout = (LinearLayout) findViewById(R.id.playAgainLayout);
                                TextView winnerMessage = (TextView) findViewById(R.id.winnerMessage);
                                winnerMessage.setText( winner +" has won!");
                                layout.setVisibility(View.VISIBLE);




            } else {

                boolean gameIsOver = true;
                for(int counterState : gameState){

                    if(counterState == 2) gameIsOver = false;


                }
                if(gameIsOver){

                    LinearLayout layout = (LinearLayout) findViewById(R.id.playAgainLayout);
                    TextView winnerMessage = (TextView) findViewById(R.id.winnerMessage);
                    winnerMessage.setText( "It's a draw!");
                    layout.setVisibility(View.VISIBLE);

                }
            }
        }

    }


}

Answer 1

winningPositions包含您可以举行以赢得比赛的所有可能的场组合（三行，三列和两个对角线）。您的代码会迭代这些winningPositions，并且每次检查是否所有三个字段都由同一个人持有，并且此人不是一个人（//2 mean unplayed）。

Answer 2

此游戏中的赢家应该在垂直，对角线或水平线上连续匹配3个符号（十字或圆形）。请参阅随附的图像，其中玩圈的玩家在每张图片中都是赢家。

[ Diagonal match match[2]

Answer 3

基本上它的作用是：对于每个获胜状态（每个可能的三个框的行），它想知道它们是否具有相同的状态（X，O或无效），并且它们是否无效（这是我认为数字2的含义）

任何人都能解释一下tic tac toe获胜的条件吗？

3 个答案: