Question

我在学习如何使用Scrapy，同时提升我的Python知识？/从学校编码。

目前，我正在使用imdb top 250列表但正在努力使用JSON输出文件。

我目前的代码是：

 # -*- coding: utf-8 -*-
import scrapy

from top250imdb.items import Top250ImdbItem


class ActorsSpider(scrapy.Spider):
    name = "actors"
    allowed_domains = ["imdb.com"]
    start_urls = ['http://www.imdb.com/chart/top']

    # Parsing each movie and preparing the url for the actors list
    def parse(self, response):
        for film in response.css('.titleColumn'):
            url = film.css('a::attr(href)').extract_first()
            actors_url = 'http://imdb.com' + url[:17] + 'fullcredits?ref_=tt_cl_sm#cast'
            yield scrapy.Request(actors_url, self.parse_actor)

    # Finding all actors and storing them on item
    # Refer to items.py
    def parse_actor(self, response):
        final_list = []
        item = Top250ImdbItem()
        item['poster'] = response.css('#main img::attr(src)').extract_first()
        item['title'] = response.css('h3[itemprop~=name] a::text').extract()
        item['photo'] = response.css('#fullcredits_content .loadlate::attr(loadlate)').extract()
        item['actors'] = response.css('td[itemprop~=actor] span::text').extract()

        final_list.append(item)

        updated_list = []

        for item in final_list:
            for i in range(len(item['title'])):
                sub_item = {}
                sub_item['movie'] = {}
                sub_item['movie']['poster'] = [item['poster']]
                sub_item['movie']['title'] = [item['title'][i]]
                sub_item['movie']['photo'] = [item['photo']]
                sub_item['movie']['actors'] = [item['actors']]
                updated_list.append(sub_item)
            return updated_list

我的输出文件给了我这个JSON组合：

[
  {
    "movie": {
      "poster": ["https://images-na.ssl-images-amazon.com/poster..."], 
      "title": ["The Shawshank Redemption"], 
      "photo": [["https://images-na.ssl-images-amazon.com/photo..."]], 
      "actors": [["Tim Robbins","Morgan Freeman",...]]}
    },{
    "movie": {
      "poster": ["https://images-na.ssl-images-amazon.com/poster..."], 
      "title": ["The Godfather"], 
      "photo": [["https://images-na.ssl-images-amazon.com/photo..."]], 
      "actors": [["Alexandre Rodrigues", "Leandro Firmino", "Phellipe Haagensen",...]]}
  }
]

但我希望实现这一目标：

{
  "movies": [{
    "poster": "https://images-na.ssl-images-amazon.com/poster...",
    "title": "The Shawshank Redemption",
    "actors": [
      {"photo": "https://images-na.ssl-images-amazon.com/photo...",
      "name": "Tim Robbins"},
      {"photo": "https://images-na.ssl-images-amazon.com/photo...",
      "name": "Morgan Freeman"},...
    ]
  },{
    "poster": "https://images-na.ssl-images-amazon.com/poster...",
    "title": "The Godfather",
    "actors": [
      {"photo": "https://images-na.ssl-images-amazon.com/photo...",
      "name": "Marlon Brando"},
      {"photo": "https://images-na.ssl-images-amazon.com/photo...",
      "name": "Al Pacino"},...
    ]
  }]
}

在我的items.py文件中，我有以下内容：

import scrapy


class Top250ImdbItem(scrapy.Item):
    # define the fields for your item here like:
    # name = scrapy.Field()

    # Items from actors.py
    poster = scrapy.Field()
    title = scrapy.Field()
    photo = scrapy.Field()
    actors = scrapy.Field()
    movie = scrapy.Field()
    pass

我了解以下事项：

我的结果没有按顺序出现，网页列表中的第一部电影始终是我输出文件中的第一部电影，但其余部分则没有。我还在努力。
我可以做同样的事情但是使用Top250ImdbItem（），仍然以更详细的方式浏览如何完成。
这可能不是我的JSON的完美布局，建议是受欢迎的，或者如果是，请告诉我，即使我知道没有完美的方式或＆＃34;唯一的方式＆＃34;。
有些演员没有照片，实际上会加载不同的CSS选择器。现在，我想避免达到＆＃34;没有图片缩略图＆＃34;所以把这些物品留空是可以的。

示例：

{"photo": "", "name": "Al Pacino"}

Answer 1

问题：...正在努力使用JSON输出文件

注意：无法使用ActorsSpider，获取错误：不支持伪元素。

# Define a `dict` **once**
top250ImdbItem = {'movies': []}

def parse_actor(self, response):
    poster = response.css(...
    title = response.css(...
    photos = response.css(...
    actors = response.css(...

    # Assuming List of Actors are in sync with List of Photos
    actors_list = []
    for i, actor in enumerate(actors):
        actors_list.append({"name": actor, "photo": photos[i]})

    one_movie = {"poster": poster,
                 "title": title,
                 "actors": actors_list
                }

    # Append One Movie to Top250 'movies' List
    top250ImdbItem['movies'].append(one_movie)

Scrapy - 创建嵌套的JSON对象

1 个答案: