Question

我有一个包含两个枚举的userModel。我为它们编写了一个自定义枚举处理程序。当选择userModel时，处理程序获取第二个枚举类型，但第一个枚举类型列名称。因此，有错误。你知道怎么解决这个问题吗？

我的经纪人：

@MappedTypes({UserType.class, AccountType.class})
public class HasValueEnumTypeHandler<E extends Enum<E> & HasValue> extends BaseTypeHandler<E> {
private Class<E> type;
private final E[] enums;
private final Logger logger = Logger.getLogger(this.getClass());

public HasValueEnumTypeHandler(Class<E> type) {
    if (type == null)
        throw new IllegalArgumentException("Type argument cannot be null");
    this.type = type;
    this.enums = type.getEnumConstants();
    if (this.enums == null)
        throw new IllegalArgumentException(type.getSimpleName() + " does not represent an enum type.");
}


@Override
public E getNullableResult(ResultSet rs, String columnName) throws SQLException {
    int value = rs.getInt(columnName);
    if (rs.wasNull()) {
        return null;
    }
    for (E enm : enums) {
        if (value == enm.getValue()) {
            return enm;
        }
    }
    throw new IllegalArgumentException("Cannot convert " + value + " to " + type.getSimpleName());
}

@Override
public E getNullableResult(ResultSet rs, int columnName) throws SQLException {
    int value = rs.getInt(columnName);
    if (rs.wasNull()) {
        return null;
    }
    for (E enm : enums) {
        if (value == enm.getValue()) {
            return enm;
        }
    }
    throw new IllegalArgumentException("Cannot convert " + value + " to " + type.getSimpleName());
}

@Override
public E getNullableResult(CallableStatement cs, int columnName) throws SQLException {
    int value = cs.getInt(columnName);
    if (cs.wasNull()) {
        return null;
    }
    for (E enm : enums) {
        if (value == enm.getValue()) {
            return enm;
        }
    }
    throw new IllegalArgumentException("Cannot convert " + value + " to " + type.getSimpleName());
}

@Override
public void setNonNullParameter(PreparedStatement ps, int i, E parameter, JdbcType jdbcType) throws SQLException {
    ps.setInt(i, parameter.getValue());
}

}

我的mapper.xml：

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE mapper PUBLIC "-//mybatis.org//DTD Mapper 3.0//EN" "http://mybatis.org/dtd/mybatis-3-mapper.dtd" >
<mapper namespace="com.rmword.mapper.UserModelMapper">

<resultMap type="com.rmword.model.UserModel" id="usermap">
    <id column="user_id" property="userId" />
    <result column="password" property="password" />
    <result column="token" property="token" />
    <result column="register_time" property="registerTime" />
    <result column="user_type" property="userType"
        typeHandler="com.rmword.utils.HasValueEnumTypeHandler" />
    <result column="account_type" property="accountType"
        typeHandler="com.rmword.utils.HasValueEnumTypeHandler" />
</resultMap>

<insert id="insertUser">
    insert into user (user_id, password, token,
    register_time, user_type, account_type) values (
    #{userId},
    #{password}, #{token}, #{registerTime},
    #{userType, typeHandler=com.rmword.utils.HasValueEnumTypeHandler},
    #{accountType,
    typeHandler=com.rmword.utils.HasValueEnumTypeHandler}
    )
</insert>

<select id="selectUserById" parameterType="String" resultMap="usermap">
    select * from user where user_id = #{userId}
</select>

我的两个枚举：

public enum AccountType implements HasValue {
EMAIL(1),
QQ(2),
WEIBO(3);

int value;

AccountType(int value) {
    this.value = value;
}

public int getValue() {
    return value;
}
}

public enum UserType implements HasValue {
RMWORD(1);

int value;

UserType(int value) {
    this.value = value;
}

public int getValue() {
    return value;
}
}

错误是

org.mybatis.spring.MyBatisSystemException: nested exception is org.apache.ibatis.reflection.ReflectionException: Could not set property 'userType' of 'class com.rmword.model.UserModel' with value 'EMAIL' Cause: java.lang.IllegalArgumentException: argument type mismatch

它混合了两个枚举。

Answer 1

可能此问题已通过https://github.com/mybatis/mybatis-3/issues/42解决。

mybatis枚举自定义处理程序错误

1 个答案: