Question

我必须查询285个ID和路径。乍一看，ID没有真正的模式，我不确定是否有办法通过简单而优雅的查询实现这一目标。

但是，我不是专家，仍在学习SQL。所以，希望得到一些指导。

以下是我想要匹配的前50个参赛作品的摘录：

        ID  path
    261617  /About/Factfile
    31  /About/Factfile/18060
    761 /About/Factfile/18060/11550
    762 /About/Factfile/18060/11552
    763 /About/Factfile/18060/11555
    35  /About/Factfile/scotlandsnapshot
    63  /About/Government/background
    74  /About/Government/sgprevious
    1555    /About/Government/sgprevious/2007-2011
    328782  /About/Government/sgprevious/2011-2016
    1553    /About/Government/sgprevious/sgprevious1999-2003
    1554    /About/Government/sgprevious/sgprevious2003-2007
    46  /About/Information/expenditure
    271169  /About/Information/expenditure/GPC
    329992  /About/Information/expenditure/GPC/epc500-16-17
    297247  /About/Information/expenditure/GPC/GPC
    297249  /About/Information/expenditure/GPC/GPC/GPC
    297243  /About/Information/expenditure/GPC/GPC500
    271168  /About/Information/expenditure/over-25k
    1550    /About/Information/expenditure/over-25k/background
    1551    /About/Information/expenditure/over-25k/reports
    22138   /About/Information/expenditure/over-25k/reports/2011-2012
    291275  /About/Information/expenditure/over-25k/reports/expenditure
    22137   /About/Information/expenditure/over-25k/reports/Expenditure2010
    266779  /About/Information/expenditure/over-25k/reports/reports
    303729  /About/Information/expenditure/over-25k/reports/Test
    316271  /About/Information/expenditure/over-25k/reports/Test1
    276826  /About/Information/expenditure/PSRA2010
    293815  /About/Information/expenditure/PSRA2010/2011-12-PSRduties
    318093  /About/Information/expenditure/PSRA2010/duties-13-14
    311621  /About/Information/expenditure/PSRA2010/duties-2012-13
    294347  /About/Information/expenditure/PSRA2010/historic-efficiency-reports
    276831  /About/Information/expenditure/PSRA2010/historicexpenditure10-11and11-12
    261611  /About/People
    23769   /About/People/14944/Events-Engagements/MinisterialEngagements
    148038  /About/People/14944/Events-Engagements/MinisterialEngagements/2008
    148037  /About/People/14944/Events-Engagements/MinisterialEngagements/2009
    148036  /About/People/14944/Events-Engagements/MinisterialEngagements/2010
    148039  /About/People/14944/Events-Engagements/MinisterialEngagements/201112
    268177  /About/People/14944/Events-Engagements/MinisterialEngagements/2012-13
    296737  /About/People/14944/Events-Engagements/MinisterialEngagements/2013-14Engagements
    304646  /About/People/14944/Events-Engagements/MinisterialEngagements/2014-15Engagements
    317634  /About/People/14944/Events-Engagements/MinisterialEngagements/MinisterialEngagements
    987 /About/People/14944/Special-Advisers
    254426  /About/People/14944/Special-Advisers/gifts-hospitality
    1048    /About/People/14944/travel
    23479   /About/People/14944/travel/airtravel
    23481   /About/People/14944/travel/ferrytravel
    23483   /About/People/14944/travel/MinisterialCarJourneys
    148029  /About/People/14944/travel/MinisterialCarJourneys/2010-11

这应该分为2个查询，1个用于ID，另一个用于路径吗？

先谢谢大家，如果这是n00b的话，请原谅我。

亲切的问候，

V

Answer 1

SELECT id, path
    FROM tbl
    ORDER BY path
    LIMIT 285;

我可以在一个优雅的SQL查询中查询285个ID和URL

1 个答案: