以下是我的示例数据：
....[a bunch of promises].then(activityF).then(activityG).then(activityH).then(function(doc){console.log(doc);});
我想用“type”中的每个字符串替换xxx。现在我使用gsub函数如下，但它一次只能替换一个查询。
root <- c("how to manage xxx","how to run xxx","how to operate xxx")
type <- c("resturant","grocery store","retail store")
结果应该是：
kw <- gsub("xxx", "123", root)
答案 0 :(得分：5)
// services/auth.service.ts
import { Injectable, NgZone } from '@angular/core';
import {Router} from '@angular/router';
import { tokenNotExpired } from 'angular2-jwt';
// We want to avoid any 'name not found'
// warnings from TypeScript
declare var Auth0Lock: any;
@Injectable()
export class AuthenticationService {
constructor( private _router: Router, private _zone: NgZone) {}
lock = new Auth0Lock('gpnhOqi20kE7pOM61DYI6BuI93ZjgA4j', 'jasont8.auth0.com');
login() {
this.lock.show((error: string, profile: Object, id_token: string) => {
if (error) {
console.log(error);
}
// We get a profile object for the user from Auth0
localStorage.setItem('profile', JSON.stringify(profile));
// We also get the user's JWT
localStorage.setItem('id_token', id_token);
});
}
logout() {
// To log out, we just need to remove
// the user's profile and token
localStorage.removeItem('profile');
localStorage.removeItem('id_token');
}
loggedIn() {
return tokenNotExpired();
}
}
魔术：
regmatches<-如果您需要创建新值，则需要首先重复原始regmatches(root, regexpr("xxx",root)) <- type
root
#[1] "how to manage resturant" "how to run grocery store"
#[3] "how to operate retail store"
向量：
root答案 1 :(得分：2)
data.frame(x = unlist(lapply(type, function(x) gsub("xxx",x,root))))
# x
#1 how to manage resturant
#2 how to run resturant
#3 how to operate resturant
#4 how to manage grocery store
#5 how to run grocery store
#6 how to operate grocery store
#7 how to manage retail store
#8 how to run retail store
#9 how to operate retail store