Question

这是我用来根据枚举类型选择功能的方法。会不会有我没有切换CalcMe功能的方法？

namespace ClassLibrary1
{
public class Playbox
{
    //types:
    //0 - red hair
    //1 - blue hair

    //defines function to input based on hairtype.
    //red:
    // input*10
    //blue:
    // input*12

    public enum Phenotypes
    {
        red,
        blue
    }

    static public int Red(int input)
    {
        return input*10;
    }

    static public int Blue(int input)
    {
        return input*12;
    }

    static public int CalcMe(Phenotypes phenotype, int input)
    {
        switch (phenotype)
        {
            case Phenotypes.red:
                return Red(input);
            case Phenotypes.blue:
                return Blue(input);
            default:
                return 0;
        }
    }

    public class MyObject
    {
        int something;
        Phenotypes hairtype;

        public MyObject()
        {
            Random randy = new Random();
            this.hairtype = (Phenotypes)randy.Next(2); //random phenotype
            this.something = CalcMe(hairtype, randy.Next(15)); //random something
        }
    }
}
}

Answer 1

您可以使用这样的词典

Dictionary<Phenotypes, Func<int, int>> Mappings = new Dictionary<Phenotypes, Func<int, int>>()
{
    {Phenotypes.red, x=> Red(x) },
    {Phenotypes.blue, x=> Blue(x) }
};

现在您可以将其称为

var something = Mappings[Phenotypes.blue](666);

Answer 2

假设：

//types:
//0 - red hair
//1 - blue hair

你可以这样做：

static public int CalcMe(Phenotypes phenotype, int input)
{
    return input * 10 + 2* (int)phenotype;
}

Answer 3

如果它只是值乘法，则只需将整数值赋给那些枚举类型

public enum Phenotypes
{
    red = 10,
    blue = 12
}

然后您需要做的就是使用它们的整数值

Phenotypes[] phenoTypeArray = new Phenotypes[]{ red, blue};

public MyObject()
{
    Random randy = new Random();
    this.hairtype = phenoTypeArray[randy.Next(2)]; //random phenotype
    this.something = (int)hairtype * randy.Next(15);
}

使用基于枚举值的函数？

3 个答案: