C编译器不会通过键盘读取字符输入

Question

我尝试制作一个类似游戏的程序，检查通过键盘输入的字符（在三秒的时间限制内）是否与随机生成的输出相同或没有。我使用的是TC ++（最新版）。

请在阅读以下内容之前先阅读本守则。

第二次，无论我输入什么字符（正确或错误），程序都说输入的字符是错误的。它没有转到scanf（也许），因为它打印＆＃34; Q＆＃34;然后＆＃34; OOPS＆＃34;线
- - - - - - - - - - - - - - - - - - 码 - - - - - - - ------------------------

#include <stdio.h>
#include<conio.h>
#include<time.h>


void main()
{
    int count , sec;
    char output, input;
    clock_t start, end;

    clrscr();

    restart:
    count = 0;

    next:
    //Generating random letters and symbols: ASCII characters from A-z 
    //Set output to A
    output = 'A';
    //Adding a value from 1-57 to get a random ASCII character from A-z
    output += rand() % 57;
    printf("%c\n",output);

    start = clock();
    scanf("%c",&input);
    end = clock() - start;
    sec = end / CLK_TCK;
    //Time limit check (Time in seconds)
    if(sec >= 3)
    {
        printf("\nYou ran out of time.");
        goto endgame;
    }

    if(input == output)
    {
        count++;
        goto next;
    }

    else
    {
        printf("\nOOPS! You are wrong\n\nYour Score is %d",count*10);
        goto endgame;
    }

    endgame:

    printf("\nDo you want to restart?(Y/N)");
    scanf("%c",&input);

    if(input == 'y' || input == 'Y')
    {
        goto restart;
    }

    getch();
}

OUTPUT:
    E
    *I enter E*
    Q
    *CONSOLE DOESN'T WAIT FOR ME TO ENTER ANYTHING*
    OOPS! You are wrong.

    Your score is 10.
    Do you want to restart(Y/N)?

Answer 1

感谢@xing和@jxh，我得到了我的愚蠢错误.. 控制台太过显着“\ n”，scanf（“％c”）; ％c之前的空间做了这个伎俩， 感谢大家！