将Python字典转换为List，其中dict键位于列表的第一个索引处

Question

我有下面的词典列表，

[
    {
        "animal": "lion",
        "color": "yellow"
    },
    {
        "animal": "elephant",
        "color": "black" 
    }
]

我需要输出作为列表的列表，格式如下，

[
    ["animal","color"],
    ["lion","yellow"],
    ["elephant","black"]
]

Answer 1

首先，从列表中的第一个字典中提取密钥。然后，通过将这些键应用于每个字典来构建列表。

keys = sorted(list_of_dicts[0].keys())
table = [keys] + [[d[k] for k in keys] for d in list_of_dicts]
# [['animal', 'color'], ['lion', 'yellow'], ['elephant', 'black']]

Answer 2

你可以试试这个：

import itertools
l = [
 {
   "animal": "lion",
    "color": "yellow"
 },
 {
    "animal": "elephant",
    "color": "black"
 }
]

headers = list(set(itertools.chain.from_iterable([i.keys() for i in l])))

headers.extend([i.values() for i in l])
print(headers)

输出：

[['animal', 'color'], ['lion', 'yellow'], ['elephant', 'black']]