Question

sql calc发现mysqli中的行没有返回确切的记录数（numrange）。我得到：1。它应该可以正常工作。

$sQuery1 = "SELECT SQL_CALC_FOUND_ROWS
            sv_cam.image,
            sv_cam.cam_id,
            sv_cam.alt,
            sv_orte.resort,
            sv_orte.resort_us,        
            sv_country.sym,
            DATE_FORMAT(sv_cam.lud, '%b %d') as stat
      FROM  sv_cam
      LEFT JOIN sv_orte ON sv_cam.res_id = sv_orte.res_id AND status=0
      INNER JOIN sv_canton ON sv_orte.can_id = sv_canton.can_id
      INNER JOIN sv_country ON sv_canton.cou_id = sv_country.cou_id
      WHERE (lud >= DATE_SUB('$today', INTERVAL 30 DAY))  ORDER BY lud desc, sv_cam.cam_id desc LIMIT $offset, $cams";
//echo $sQuery1;
$sResult1=mysqli_query($conn, $sQuery1);
$numrows = mysqli_num_rows($sResult1);
//if ($numrows<1) { exit; }


$numrange=mysqli_query($conn,"SELECT FOUND_ROWS()");
echo $numrange;

Answer 1

mysql_query()函数返回mysqli_result个对象。因此，您需要获取结果。

$sResult2 = mysqli_query($conn, 'SELECT FOUND_ROWS() AS total');
$found_rows = mysqli_fetch_object($sResult2);

echo 'total rows'.$found_rows->total;

sql calc发现mysqli中的行没有返回确切的记录数

1 个答案: