Question

我需要将毫秒值85605304.3587转换为0d 18h 21m的值。不知道如何开始，有没有类似于SQL中的TimeSpan，就像在C＃中那样？

Answer 1

您可以明确地进行计算。我认为是：

select floor(msvalue / (1000 * 60 * 60 * 24)) as days,
       floor(msvalue / (1000 * 60 * 60)) % 24 as hours,
       floor(msvalue / (1000 * 60)) % 60 as minutes

注意：有些数据库使用mod而不是%。

Answer 2

使用原生date & time functions，可能：

SELECT
    AsDateTime = DATEADD(MILLISECOND, 85605304, 0)
  , AsDateTime2 = DATEADD(NANOSECOND, 7 * 100, DATEADD(MICROSECOND, 358, DATEADD(MILLISECOND, 85605304, CONVERT(datetime2, CONVERT(datetime, 0)))))
-- Incorrect datetime2 approach I initially did, has some precision loss, probably due to datetime's millisecond issue with 0's, 3's, and 7.'s
--SELECT DontDoThis = DATEADD(NANOSECOND, 7 * 100, DATEADD(MICROSECOND, 358, CONVERT(datetime2, DATEADD(MILLISECOND, 85605304, 0))))

datetime仅涵盖超过秒的3位数，而datetime2将保持7位数。也许存在其他类似日期对象的方法，我不知道。

Answer 3

在MS SQL SERVER中，您可以使用下一个代码：

with cte as (
    select cast(85605304.3587 as int) / 1000 / 60 as [min]
), cte2 as (
    select 
        cast([min] % 60 as varchar(max)) as minutes,
        cast(([min] / 60) % 24 as varchar(max)) as hours,
        cast([min] / (60 * 24) as varchar(max)) as days
    from cte
)
select concat(days, 'd ', hours, 'h ', minutes, 'm') as tm
from cte2

SQL将毫秒转换为天，小时，分钟

3 个答案: