Question

我正在编写一个解析.txt文件并抓取用户定义输入的键/值对的程序。我的代码的逻辑非常简单。它抓取程序应搜索的字符串列表，并将字符串列表存储在其适当的变量中。我编写了一个函数field_extract来执行键/值对。

我的调试问题是＆＃34; currentJob = job_start.index（jobStart）+ 1＆＃34;。逻辑上应该可以正常工作，但由于某种原因它不会。

以下代码

n2600RA1 = []
n2600RA2 = []
n2600RA3 = []
n2600RA4 = []
n2600RA5 = []
n2601CV4 = []
n2601IV4 = []
(etc)....

job_start = []
job_end = []
names = []
name = None
pk = []

for row in rows:
    name = row[1]
    fields = row[4].split(',')
    start = row[2]
    end = row[3]
    prim = row[0]

    if name == 'JOB - N2600RA1':
        n2600RA1.extend(fields)
        job_start.append(start)
        job_end.append(end)
        pk.append(prim)
        names.append(name)

    elif name == 'JOB - N2600RA2':
        n2600RA2.extend(fields)
        job_start.append(start)
        job_end.append(end)
        pk.append(prim)
        names.append(name)

        (etc)...


"""
DATABASE CONNECTION ENDED
"""

outFileName = "out3.txt"

# The regex pattern that is used to extract timestamp from file
# it will search for timestamps like this 2017-06-13-22.31.30.978293
dateRegEx = r"[0-9]{4}-[0-9]{2}-[0-9]{2}-[0-9]{2}\.[0-9]{2}\.[0-9]{2}\.[0-9]+"
# Compile the pattern
regExPtrn = re.compile(dateRegEx)


# Extract the current job fields
def field_Extract(fileLines, fieldsArray, delimit):
    # Empty string in which we will append the
    # extracted fields
    matchStr = ""
    for line in fileLines:
        for field in fieldsArray:
            if line.startswith(field):
                key, value = line.split(delimit)
                matchStr += key.strip() + "\t\t : " + value.strip() + "\n"
    # Return the string hold the extracted fields
    # Each field is onn a separate line
    return matchStr


# Open input and output files
test_file = open(r'C:\Users\cqt7wny\Desktop\SAVERS_REPT_DT0712.txt', 'r+')
outFile = open(outFileName, 'w')

# Initialize used variables
currentJob = -1
currentJobData = []
startAppending = False
outFileStr = ""
for line in test_file:

    # Get the current job
    # We will loop over each job start and check if this start is
    # contained in the current line, if so, this line will be considered
    # the first line of the job
    for jobStart in job_start:
        if jobStart in line:
            # the used search function return the index of the first
            # match of the string. If the substring has more than one
            # occurance in the searchable string, only the index of
            # the first occurance will be returned
            currentJob = job_start.index(jobStart) + 1
            # Set the flag to start gathering job lines
            # for each job we will apped alll its lines to an empty
            # list, so we have all job lines separated
            startAppending = True

    # If job start found, gathar job lines
    if startAppending == True:
        currentJobData.append(line)

    # Set the correct job
    if currentJob == 1:
        job = n2600RA1
    elif currentJob == 2:
        job = n2600RA2
    elif currentJob == 3:
        job = n2600RA3
    elif currentJob == 4:
        job = n2600RA4
    elif currentJob == 5:
        job = n2600RA5
    elif currentJob == 6:
        job = n2601CV4
    elif currentJob == 7:
        job = n2601IV4
    elif currentJob == 8:
        job = n2601CV1
    #elif currentJob == 9:
     #   job = aTL10GV1
    elif currentJob == 9:
        job = n2601CW3
    else:
        currentJob = -1

    # Check job end
    # We will loop over each job end and check if this end is
    # contained in the current line, if so, this line will be considered
    # the last line of the job
    for jobEnd in job_end:
        # Check that this is a valid job and that the job ending
        # string is contained in the current line
        if (currentJob != -1) and (jobEnd in line):
            print(currentJob)
            # As a job end found, stop gathering lines
            startAppending = False
            # Get the time stamp
            # We search for it in the currnet line using the previously
            # compiled regex pattern
            txt = "".join(currentJobData)
            # Find all occurance of timestamps on the current job lines
            #timeStamp = regExPtrn.findall(txt)
            # Check that a timestamp found
            #if len(timeStamp) >= 1:
                # If there is more than one timestamp in the current
                # job lines, get only the first one
                #timeStamp = timeStamp[0]
            # Append the found output to the output string
            outFileStr += '########============ NEW JOB STARTS HERE ===========#########'
            outFileStr += "\n"
            outFileStr += "job# " + str(name[currentJob])
            outFileStr += "\n"
            #outFileStr += "Timestamp: " + timeStamp
            outFileStr += "\n"
            # Extract job fields values
            outFileStr += field_Extract(currentJobData, job, ':')
            # Erase completed job lines to be used with the next job
            currentJobData = []
            # Set job to invalid job
            currentJob = -1

# Write the output to output file
outFile.write(outFileStr)
# Close opened files
outFile.close()
test_file.close()

调试currentjob下面的输出。

Answer 1

你可能错过了休息时间：

for jobStart in job_start:
    if jobStart in line:
        currentJob = job_start.index(jobStart) + 1
        startAppending = True
        break  # <-- THIS!

您也应该强烈考虑简化代码。它有很多不必要的重复代码。

考虑将您的工作存储在dict中，而不是为了保存自己：（作业名称也可以从db或文本文件中获取）

jobs_names = [
    'n2600RA1', 'n2600RA2', 'n2600RA3', 'n2600RA4',
    'n2600RA5', 'n2601CV4', 'n2601IV4', 'n2601CV1',
    'aTL10GV1', 'bEL10GV1', 'cHL10GV1', 'cZL10GV1',
    'dEL10GV1', 'dKL10GV1', 'eSL10GV1', 'fIL10GV1',
    'fRL10GV1', 'gBL10GV1', 'hUL10GV1', 'iEL10GV1',
    'iTL10GV1', 'nLL10GV1', 'nOL10GV1', 'pLL10GV1',
    'pTL10GV1', 'sEL10GV1', 'n2601CW3',
]

jobs = {n: [] for n in jobs_names}
print(jobs)

输出：

{'n2600RA1': [], 'n2600RA2': [], 'n2600RA3': [], 'n2600RA4': [],
 'n2600RA5': [], 'n2601CV4': [], 'n2601IV4': [], 'n2601CV1': [],
 'aTL10GV1': [], 'bEL10GV1': [], 'cHL10GV1': [], 'cZL10GV1': [], 
 'dEL10GV1': [], 'dKL10GV1': [], 'eSL10GV1': [], 'fIL10GV1': [], 
 'fRL10GV1': [], 'gBL10GV1': [], 'hUL10GV1': [], 'iEL10GV1': [], 
 'iTL10GV1': [], 'nLL10GV1': [], 'nOL10GV1': [], 'pLL10GV1': [],
 'pTL10GV1': [], 'sEL10GV1': [], 'n2601CW3': []}

Python增量调试问题

1 个答案: