我想写一个C#函数,当我通过“Montgomery”时返回“alamaba”。
第二个例子:Sitka - >阿拉斯加
这是示例列表:
List<PopulationUSA> result = new List<PopulationUSA>();
PopulationUSA usa = new PopulationUSA("Population in USA", 316128839, new List<PopulationUSA>());
result.Add(usa);
PopulationUSA alabama = new PopulationUSA("Alabama", 4833722, new List<PopulationUSA>());
usa.Items.Add(alabama);
alabama.Items.Add(new PopulationUSA("Birmingham", 212113, null));
alabama.Items.Add(new PopulationUSA("Montgomery", 201332, null));
alabama.Items.Add(new PopulationUSA("Mobile", 194899, null));
PopulationUSA alaska = new PopulationUSA("Alaska", 735132, new List<PopulationUSA>());
usa.Items.Add(alaska);
alaska.Items.Add(new PopulationUSA("Juneau", 32660, null));
alaska.Items.Add(new PopulationUSA("Ketchikan", 8214, null));
alaska.Items.Add(new PopulationUSA("Sitka", 9020, null));
这是班级:
public class PopulationUSA
{
public PopulationUSA(string name, int value, List<PopulationUSA> items)
{
Name = name;
Value = value;
Items = items;
}
public string Name { get; set; }
public int Value { get; set; }
public List<PopulationUSA> Items { get; set; }
}
我该怎么做? 感谢
答案 0 :(得分:0)
您可以将此方法添加到PopulationUSA类
public string FindParentsOfGrandChildren(string _name)
{
List<PopulationUSA> parents = Items.Where(s => s.Items.Any(c => c.Name == _name)).ToList();
if (parents != null)
{
string listparents = string.Empty;
for (int i = 0; i < parents.Count; i++)
{
if (i == 0)
{
listparents += parents[i].Name;
}
else
{
listparents += ", " + parents[i].Name;
}
}
return listparents;
}
else
{
return "Not found";
}
}
然后在你的例子中使用它:
string WhereDoIBelong = usa.FindParentsOfGrandChildren("Montgomery")
作为递归方法会更好,找到任何类型的父母(不仅仅是“孙子”),但那是你的工作!