以下是 TOUR 表:
tour_id | tour_date | amount
------------------------------
ABC | 2016-03-07 | 100
ABC | 2016-03-15 | 200
DEF | 2016-03-07 | 300
DEF | 2016-03-15 | 100
GHI | 2016-03-07 | 30
我想得到以下内容:
此最终数据必须如下所示:
tour_id| weekly sum. | monthly sum.
--------------------------------
ABC | 100 | 300
DEF | 300 | 400
GHI | 30 | 30
答案 0 :(得分:0)
SELECT
tour_id, WEEKLY, MONTHLY
FROM
TOUR T1
INNER JOIN
(SELECT
tour_id, SUM(amount) WEEKLY
FROM
TOUR
GROUP BY tour_id , WEEK(tour_date)) WEEK ON WEEK.tour_id = T1.tour_id
INNER JOIN
(SELECT
tour_id, SUM(amount) MONTHLY
FROM
TOUR
GROUP BY tour_id , DATE_FORMAT(tour_date, '%m')) MONTH ON WEEK.tour_id = MONTH.tour_id
尝试以上查询。
答案 1 :(得分:0)
import pandas as pd
# Read csv
df = pd.read_csv("pathtocsv")
# Filter column N
df= df[df["N"] > "Y"]
# Write to csv again
df.to_csv("newcsvpath")