传递包含字符串的列表时出错

Question

抱歉，我还是个新手。试着学习python !! 我的代码 -

ScrollViewActivity.onCreate

当我尝试传递protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.scrollview); _linearLayout = (LockedLinearLayout)findViewById(R.id.Container); _scrollView = (LockedScrollView)findViewById(R.id.ScrollView); _layoutInflater = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE); _linearLayout.addOnLayoutChangeListener(new View.OnLayoutChangeListener() { @Override public void onLayoutChange(View v, int left, int top, int right, int bottom, int oldLeft, int oldTop, int oldRight, int oldBottom) { _scrollView.scrollTo(0, _scrollView.getScrollY() + (bottom - oldBottom )); } }); addExampleImage(10, _linearLayout); } -

时，

给了我一个错误

  

列表索引必须是整数，而不是str

Answer 1

我希望在我第一次学习时花更多时间了解标准库！

import collections

word_count = collections.Counter(['fizz', 'buzz'])

print(word_count['fizz'])

Answer 2

def fizz_count(x):
    count=0
    for item in range(len(x)):
        if x[item]=="fizz":
            count=count+1
    return count

或

def fizz_count(x):
    count=0
    for item in x:
        if item=="fizz":
            count=count+1
    return count